Pythagorean Triple -- from Wolfram MathWorld

Pythagorean Triple

A Pythagorean triple is a triple of positive integers , , and such that a right triangle exists with legs and hypotenuse . By the Pythagorean theorem, this is equivalent to finding positive integers , , and satisfying

(1)

The smallest and best-known Pythagorean triple is .

Plots of points in the -plane such that is a Pythagorean triple are shown above for successively larger bounds. These plots include negative values of and , and are therefore symmetric about both the x- and y-axes.

Similarly, plots of points in the -plane such that is a Pythagorean triple are shown above for successively larger bounds.

It is usual to consider only primitive Pythagorean triples (also called "reduced"triples) in which and are relatively prime, since other solutions can be generated trivially from the primitive ones. The primitive triples are illustrated above, and it can be seen immediately that the radial lines corresponding to imprimitive triples in the original plot are absent in this figure. For primitive solutions, one of or must be even, and the other odd (Shanks 1993, p. 141), with always odd.

In addition, one side of every Pythagorean triple is divisible by 3, another by 4, and another by 5. One side may have two of these divisors, as in (8, 15, 17), (7, 24, 25), and (20, 21, 29), or even all three, as in (11, 60, 61).

Given a primitive triple , three new primitive triples are obtained from

			(2)
			(3)
			(4)

where

		(5)
		(6)
		(7)

Roberts (1977) proves that is a primitive Pythagorean triple iff

(8)

where is a finite product of the matrices , , . It therefore follows that every primitive Pythagorean triple must be a member of the infinite array

( 7, 24, 25); ( 5, 12, 13) ( 55, 48, 73); ( 45, 28, 53); ( 39, 80, 89); (3, 4, 5) ( 21, 20, 29) ( 119, 120, 169); ( 77, 36, 85); ( 33, 56, 65); ( 15, 8, 17) ( 65, 72, 97); ( 35, 12, 37).

(9)

Pythagoras and the Babylonians gave a formula for generating (not necessarily primitive) triples as

(10)

for , which generates a set of distinct triples containing neither all primitive nor all imprimitive triples (and where in the special case , ).

The early Greeks gave

(11)

where and are relatively prime and of opposite parity (Shanks 1993, p. 141), which generates a set of distinct triples containing precisely the primitive triples (after appropriately sorting and ).

Let be a Fibonacci number. Then

(12)

generates distinct Pythagorean triples (Horadam 1961, Dujella 1987), although not exhaustively for either primitive or imprimitive triples.

For any Pythagorean triple, the product of the two nonhypotenuse legs (i.e., the two smaller numbers) is always divisible by 12, and the product of all three sides is divisible by 60. It is not known if there are two distinct triples having the same product. The existence of two such triples corresponds to a nonzero solution to the Diophantine equation

(13)

(Guy 1994, p. 188).

For a Pythagorean triple (, , ),

(14)

where is the partition function P (Honsberger 1985). Every three-term progression of squares , , can be associated with a Pythagorean triple ) by

			(15)
			(16)
			(17)

(Robertson 1996).

The area of a triangle corresponding to the Pythagorean triple is

(18)

Fermat proved that a number of this form can never be a square number.

To find the number of possible primitive triangles which may have a leg (other than the hypotenuse) of length , factor into the form

(19)

The number of such triangles is then

$L_p(s)={0 for s=2 (mod 4); 2^(n-1) otherwise,$

(20)

i.e., 0 for singly even and 2 to the power one less than the number of distinct prime factors of otherwise (Beiler 1966, pp. 115-116). The first few numbers for , 2, ..., are 0, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 2, 1, 0, 2, ... (Sloane's A024361). To find the number of ways in which a number can be the leg (other than the hypotenuse) of a primitive or nonprimitive right triangle, write the factorization of as

(21)

Then

$L(s)={1/2[(2a_1+1)(2a_2+1)...(2a_n+1)-1] for a_0=0; 1/2[(2a_0-1)(2a_1+1)(2a_2+1)...(2a_n+1)-1] for a_0>=1$

(22)

(Beiler 1966, p. 116). Note that iff is prime or twice a prime. The first few numbers for , 2, ... are 0, 0, 1, 1, 1, 1, 1, 2, 2, 1, 1, 4, 1, ... (Sloane's A046079).

To find the number of ways in which a number can be the hypotenuse of a primitive right triangle, write its factorization as

(23)

where the s are of the form and the s are of the form . The number of possible primitive right triangles is then

$H_p(s)={2^(r-1) for n=0 and a_0=0; 0 otherwise,.$

(24)

For example, since

			(25)
			(26)

The values of for , 2, ... are 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, ... (Sloane's A024362). The first few primes of the form are 5, 13, 17, 29, 37, 41, 53, 61, 73, 89, 97, 101, 109, 113, 137, ... (Sloane's A002144), so the smallest side lengths which are the hypotenuses of 1, 2, 4, 8, 16, ... primitive right triangles are 5, 65, 1105, 32045, 1185665, 48612265, ... (Sloane's A006278).

The number of possible primitive or nonprimitive right triangles having as a hypotenuse is

			(27)
			(28)

(correcting the typo of Beiler 1966, p. 117, which states that this formula gives the number of non-primitive solutions only), where is the sum of squares function. For example, there are four distinct integer triangles with hypotenuse 65, since

(29)

The first few numbers for , 2, ... are 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 1, 0, 1, 0, 1, 0, 0, ... (Sloane's A046080). The smallest hypotenuses having distinct triples are 1, 5, 25, 125, 65, 3125, ... (Sloane's A006339). The following table gives the hypotenuses for which there exist exactly distinct right integer triangles for , 1, ..., 5.

	Sloane	hypotenuses for which there exist distinct integer triangles
0	A004144	1, 2, 3, 4, 6, 7, 8, 9, 11, 12, 14, 16, 18, ...
1	A084645	5, 10, 13, 15, 17, 20, 26, 29, 30, 34, 35, ...
2	A084646	25, 50, 75, 100, 150, 169, 175, 200, 225, ...
3	A084647	125, 250, 375, 500, 750, 875, 1000, 1125, 1375, ...
4	A084648	65, 85, 130, 145, 170, 185, 195, 205, 221, 255, ...
5	A084649	3125, 6250, 9375, 12500, 18750, 21875, 25000, ...

Therefore, the total number of ways in which may be either a leg or hypotenuse of a right triangle is given by

(30)

The values for , 2, ... are 0, 0, 1, 1, 2, 1, 1, 2, 2, 2, 1, 4, 2, 1, 5, 3, ... (Sloane's A046081). The smallest numbers which may be the sides of general right triangles for , 2, ... are 3, 5, 16, 12, 15, 125, 24, 40, ... (Sloane's A006593; Beiler 1966, p. 114).

There are 50 Pythagorean triples with hypotenuse less than 100, the first few of which, sorted by increasing , are (3, 4, 5), (6, 8,10), (5, 12, 13), (9, 12, 15), (8, 15, 17), (12, 16, 20), (15, 20, 25), (7, 24, 25), (10, 24, 26), (20, 21, 29), (18, 24, 30), (16, 30, 34), (21, 28, 35), ... (Sloane's A046083, A046084, and A009000).

Of these, only 16 are primitive triplets with hypotenuse less than 100: (3, 4,5), (5, 12, 13), (8, 15, 17), (7, 24, 25), (20, 21, 29), (12, 35, 37), (9, 40, 41), (28, 45, 53), (11, 60, 61), (33, 56, 65), (16, 63, 65), (48, 55, 73), (36, 77, 85), (13, 84, 85), (39, 80, 89), and (65, 72, 97) (Sloane's A046086, A046087, and A020882).

Let the number of triples with hypotenuse be denoted , the number of triples with hypotenuse be denoted , and the number of primitive triples less than be denoted . Then the following table summarizes the values for powers of 10.

	Sloane	, , ...
	A101929	1, 50, 878, 12467, ...
	A101930	2, 52, 881, 12471, ...
	A101931	1, 16, 158, 1593, ...

Lehmer (1900) proved that the number of primitive solutions with hypotenuse less than satisfies

(31)

(Sloane's A086201).

The inradii of the first few primitive Pythagorean triangles ordered by increasing are given by 1, 2, 3, 3, 6, 5, 4, 10, 5, ... (Sloane's A014498).

There is a general method for obtaining triplets of Pythagorean triangles with equal areas. Take the three sets of generators as

			(32)
			(33)
			(34)
			(35)
			(36)
			(37)

Then the right triangle generated by each triple () has common area

(38)

(Beiler 1966, pp. 126-127). The only extremum of this function occurs at . Since for , the smallest area shared by three nonprimitive right triangles is given by , which results in an area of 840 and corresponds to the triplets (24, 70, 74), (40, 42, 58), and (15, 112, 113) (Beiler 1966, p. 126).

Right triangles whose areas consist of a single digit include (area of 6) and (area of 666666; Wells 1986, p. 89).

In 1643, Fermat challenged Mersenne to find a Pythagorean triplet whose hypotenuse and sum of the legs were squares. Fermat found the smallest such solution:

			(39)
			(40)
			(41)

with

			(42)
			(43)

A related problem is to determine if a specified integer can be the area of a right triangle with rational sides. 1, 2, 3, and 4 are not the areas of any rational-sided right triangles, but 5 is (3/2, 20/3, 41/6), as is 6 (3, 4, 5). The solution to the problem involves the elliptic curve

(44)

A solution (, , ) exists if (44) has a rational solution, in which case

			(45)
			(46)

(Koblitz 1993). There is no known general method for determining if there is a solution for arbitrary , but a technique devised by J. Tunnell in 1983 allows certain values to be ruled out (Cipra 1996).

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Cipra, B. "A Proof to Please Pythagoras." Science 271, 1669, 1996.

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Wells, D. The Penguin Dictionary of Curious and Interesting Numbers. New York: Penguin Books, 1986.

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Weisstein, Eric W. "Pythagorean Triple." From MathWorld--A Wolfram Web Resource. http://mathworld.wolfram.com/PythagoreanTriple.html