ASTR 130 (O'Connell) Lecture Notes
3. MOTIONS IN THE SKY & COORDINATE SYSTEMS
Star trails around South Celestial Pole
in 10 hour exposure.
A. MOTIONS OF BRIGHT OBJECTS
In the first lecture, we described the main astronomical phenomena
which are visible in the sky to the naked eye as background for Lab
1. In the last lecture, we detoured to discuss telescopes &
binoculars, to give you background for Labs 2, 3 & 4. Telescopes go
far beyond the limits of the human eye to reveal an amazingly rich
trove of new phenomena. Today, we return to the subjects of the first
lecture and consider the origins of the motions of naked eye
objects.
This material is basic to all the lab work, but there is a substantial
amount of it. I recommend you read over the class notes in conjunction
with Appendices A and B in the Manual first quickly and later more
carefully. Test your understanding using the set of review questions
posted on the web site (see Homework below).
Cyclical motions of bright objects in sky were the main
historical stimulus for the study of astronomy. We first describe
these motions as they might have been seen by ancient astronomers but
then explain them from a modern perspective.
The table below lists celestial motions which are easily detectable by
someone on the Earth without telescopes. We call these
apparent motions, because they can be produced by motions of
the observer as well as by the objects themselves.
| OBJECT |
PERIOD |
MOTION* |
| ALL |
Daily ("diurnal") |
Rotation Westward |
| SUN |
Annual (365 d) |
(i) 1 degree/day Eastward |
| (ii) North/South |
| MOON |
Monthly (29d) |
(i) Eastward, N/S |
| (ii) Phase change |
| PLANETS |
Months-Years |
Generally Eastward, but complex |
*Motions are measured with respect to the stars, except for the diurnal motion,
which is with respect to the local horizon.
Most of these motions are so slow that if you aren't a practicing
amateur astronomer, you probably aren't aware of them. The best way
to visualize them is in a planetarium or with a good computer sky
simulation program. We will use Starry Night to illustrate
them in class.
- The motions may be complicated, but they are repeatable
over periods of months to years. It was this cyclic nature that
encouraged early astronomers to seek a deeper understanding of them.
If the easily observable sky phenomena had been random in character,
science might never have developed, and superstition might still
prevail. The famous science fiction story "Nightfall" by Isaac Asimov
describes what might befall a society whose planet was less
fortunately situated than ours (such that darkness occurs only every
2000 years).
B. EXPLANATION OF MOTIONS
In the rest of this lecture, we explain these phenomena from a
modern scientific perspective. It took many centuries for
astronomers to arrive at the correct interpretation described here.
Ancient Greek astronomers understood most of this after several hundred
years of work, but the knowledge was lost and only rediscovered during
the Renaissance, 1300 years later.
The key to complete understanding of celestial motions was introduced
by the Greeks: mathematics. The Greeks built mathematical models
of the sky based on the concepts in plane and later spherical geometry which
they had developed. These reduce a bewildering array of complex phenomena to
a much simpler set of mathematical concepts.
The apparent motions of celestial objects are produced by
two entirely different effects:
- Intrinsic motions of the objects themselves with respect
to one another
- The motion of the observer, or the platform on which
he/she is standing---in this case, the Earth
The apparent motions we discuss in this lecture are all in the
second category: we observe the universe from a round, tilted,
spinning, moving platform. It is difficult for most people to
visualize this situation or to separate Earth's motion from intrinsic
motions of the cosmic bodies. This is one of the main obstacles to
overcoming primitive flat-Earth cosmologies.
C. EFFECTS OF EARTH SHAPE AND SPIN
- Earth is a sphere.
- Night = shadow side (away from Sun). Half of Earth is always
in shadow.
- Daylight = sunlight scattered by Earth's atmosphere.
Daylight glare overwhelms the light of the planets and stars, so we
cannot see them when the Sun is above the horizon.
- Earth spins on its axis with respect to the stars once in 23 hours, 56
minutes (one "sidereal day"). This causes the apparent diurnal rotation of sky.
The universe is not moving around the Earth once per day.
- The spin is counterclockwise (eastward) as seen from
above N pole; ==> apparent rotation of sky is westward
- Left-hand panel of diagram above shows Earth viewed from above its
North Pole. The Earth rotates counterclockwise in this diagram,
carrying observers with it. The positions where observers on the
equator are experiencing sunrise, noon, sunset, and midnight are
marked. Mean local times of day corresponding to these points are
6 AM, 12 noon, 6 PM, and 12 midnight, respectively.
- The right hand panel shows the local "horizon plane,"
which is the plane "tangent" to Earth at your location. You can see
(in principle) objects above the plane but not below. Note that
half of the entire celestial sphere is always
above your horizon plane. However, the horizon plane (and visible
hemisphere) is different at each location on Earth. The
horizon plane sweeps across sky as Earth spins and determines the
rising and setting of objects. Objects rise over the eastern horizon
and set toward the western horizon.
- By combining the concept of the horizon plane with the definition
of local time in the left-hand panel, you can visualize what
parts of the sky are observable at any given time.
D. EFFECTS OF EARTH'S MOTION IN ORBIT
- Earth is a planet moving in orbit around the Sun
- Orbit is nearly circular (distance to Sun varies only 3%)
- Orbit lies in a plane called the "ecliptic" plane. Seen
face-on, the orbit is technically an ellipse but deviates only
slightly from a circle. Seen edge-on, the orbit is a thin line.
- Earth orbits Sun in 365.25 days (one year) moving at ~66,000 mph.
Motion is counterclockwise as seen from above N. pole
- Stars visible at night are those "opposite" the Sun. See figures
above. The night side of Earth is that opposite the Sun. So, in May,
the constellation Scorpio will be prominent in the night sky, while in
November, it lies in the direction of the Sun and therefore is not
visible because of the atmospheric glare.
- Warning! this drawing, and most others you
will see in this course and in astronomy texts, is grossly distorted
and not to scale! In reality, the Earth's orbit is 100 times the
diameter of the Sun; the Earth is 100 times smaller than the Sun; the
stars are vastly distant from the Earth's orbit; and the stars in a
given constellation are not necessarily near one another in space.
We are viewing Earth's orbit here from an angle such that it looks
highly elliptical, whereas it is nearly circular seen face-on.
Obviously, no one could produce or sensibly view a figure like this
drawn to actual scale.
- The Earth's motion around the Sun is counterclockwise in the
drawings above. This produces an apparent eastward "motion" of the
Sun as seen from the Earth against the stellar reference frame. In
the drawings, the Sun in November would be seen in projection against
Libra (if you could be outside the Earth's atmosphere), while in
December, the Earth has moved such that the Sun is seen in projection
against Scorpio. The average "motion" of the Sun against the stars is
1 degree per day eastward.
- "Solar" vs. "sidereal" days: The daily motion of the Earth in its
orbit means that the Earth must spin a little more than once
on its axis to bring the Sun back to the point of local "noon" (i.e.
halfway between rise and set). The extra amount is 4 minutes, on
average. This accounts for the difference between the sidereal
rotation period of the Earth (23 hours, 56 min) and the average
difference between successive noons (24 hours, the "solar day").
[See illustration of effect of Earth's motion during one sidereal
day here.]
- The Sun's location on the sky as seen from Earth is confined to
the ecliptic path = the projection of the ecliptic plane on
the celestial sphere.
- The "Zodiac" is the set of constellations through which
the ecliptic path passes. (See Lecture 1.) Those are the only
constellations which have been illustrated in the drawings above. Of
course, there are 76 other constellations not shown. You should
know the names of the Zodiacal constellations.
E. EFFECTS OF TILT OF EARTH'S AXIS
- The polar rotation axis of the Earth is not perpendicular to
its orbital plane. It is tilted by 23.5 degrees. See figure
below (again, exaggerated for clarity):
- The rotation axis is fixed in direction with respect to the
stars, not with respect to the Sun. This means that, as Earth
orbits the Sun, the axis continues to point in the same direction
in 3D space.
- This implies that the Sun, as viewed from the Earth, will appear
to move north and south of the celestial equator through the year by a
maximum of + or - 23.5 degrees. In the drawing above, if the North
Pole is at the top, the Sun will be seen at its most southerly
position. The total amplitude of the swing = 2 x 23.5 = 47 degrees.
- Equivalently, the ecliptic path is
inclined 23.5 degrees to the celestial equator. The following
diagram shows the ecliptic and the equator on the celestial sphere (see
Lecture 1 for the definition of the celestial
sphere).
- The ecliptic crosses the celestial equator at two points
called equinoxes.
- When the Sun is at an equinox, night and day are each 12 hours
long at all latitudes. The "Vernal Equinox" occurs around March 21,
while the "Autumnal Equinox" occurs around September 21.
- The Sun is at its greatest distance from the equator (23.5
degrees) at the solstices ("sun stationary," approx. June 21, Dec
21). At these times, one hemisphere experiences its longest day,
the other its shortest.
- The Sun's N/S distance determines the hours of daylight and the
angle at which sunlight strikes Earth's surface. It thus determines
"insolation," or the amount of sunlight incident on a unit area of the
Earth's surface during 24 hours. This differential heating is responsible
for the seasons. The "official" beginning dates of spring, summer,
autumn, and winter correspond to the Vernal Equinox, Summer Solstice,
Autumnal Equinox, and Winter Solstice, respectively.
- The change in the geographic shadow distribution caused by
the tilt is quite dramatic (even though the shadow always covers
exactly one hemisphere of the Earth). Here are two images of the way
the shadow is distributed at about 2 PM Eastern time on August 1
(left) and December 1 (right). The Earth's surface moves eastward through
the shadow. You can immediately tell from the image which latitudes are
receiving more sunlight in a 24 hour period. Click on the thumbnails
for an expanded view.
- Therefore, seasons are caused by tilt, not distance to the
Sun. If the seasons were a distance effect, winter, for
instance, would occur simultaneously in both the southern and northern
hemispheres; but instead, the seasons differ by 6 months in the two
hemispheres. The Earth is actually nearest the Sun in January, one of
the coldest months in the northern hemisphere.
F. ASTRONOMICAL COORDINATE SYSTEMS
Right Ascension and Declination
- The astronomical coordinate system is similar to the terrestrial
two-angle coordinate system for finding places on the Earth's
surface. The terrestrial angular coordinates are
latitude, for measuring north-south distances, and
longitude, for measuring east-west distances.
- The celestial Equatorial Coordinate System is very similar. It
uses two angles to measure positions on the celestial sphere.
Declination is analogous to latitude, while Right
Ascension is analogous to longitude.
- As seen in the figure above, declination (abbreviated DEC or Greek
"delta") is measured (in degrees) north or south of the celestial
equator. The North and South celestial poles have DECs of +90
and -90 degrees, respectively. The equator has DEC 0.
- Right Ascension (RA or Greek "alpha") is measured as shown
in the figure above. Lines of constant RA are great circles (also
called "hour circles") drawn through the celestial poles. The zero
point of RA is the vernal equinox, and RA increases
eastward. (This is an arbitrary designation, just like the
zero point of the longitude system is arbitrarily chosen to be
Greenwich, England.)
- Rather than measuring in degrees, RA is measured in time
units of hours, minutes, and seconds up to one sidereal
day. Therefore, RA values run from 0 hours to
23h59m59s. For a star on the equator,
one hour of RA corresponds to 15 degrees of arc. But because of
the convergence of the lines of constant RA toward the pole (see figure
above), at other declinations one hour of RA corresponds to fewer
than 15 degrees of arc. (Beware confusion between "minutes" and
"seconds" of time and those of arc!).
Visibility of Astronomical Objects: Declination & Hour Angle
It is important to know how to determine when astronomical
objects are well placed for observation from your particular location
on Earth at a given date and time. The "DEC-HA"
method is the quickest way to do this:
- The figure above shows how the declination of an astronomical
object controls its visibility with respect to your horizon. The
shaded plane is the horizon. Star tracks are shown on the celestial
sphere. The orientation of the sphere for your location is the
same at all times of the year (though the Sun moves to
different locations along it and thus changes the part of it which is
visible at night).
- As the Earth rotates on its axis during the course of a night, the
stars appear to rise in the east, move along the heavy lines of
constant declination, and set in the west. A star is farthest
from the horizon when it crosses your meridian (see Lecture 1). At this time it is
said to transit.
- The figure above helps you visualize how long in each 24 hour period
stars at different DECs are above your horizon. Some DECs (like +60
degrees here) are always above your horizon. Stars here are
called circumpolar stars; they never set. By contrast, stars
at -30 degrees DEC are above the horizon only for short periods. There
are some stars farther south which are never above your horizon.
- Knowing DEC alone is not sufficient. The celestial sphere
rotates continuously about the axis through its poles and therefore
continuously changes the location of an astronomical object in your
local coordinate system. An object's DEC may always be the same, but
its east-west position changes during the night. To locate an
astronomical object in the sky, you need to know one additional
quantity besides DEC: the distance of its hour circle from your local
meridian.
- The Hour Angle or HA is defined to be the angle
measured along the equator between the hour circle of a star and your
meridian. In the diagram above, the hour angle is denoted "H." It
is quoted in time units (hours, minutes, and seconds), and is
numerically equal to the time elapsed since the last transit of
the star.
Objects to the west of the meridian have
positive HA, while objects to the east have
negative HA. A star with HA = 2 crossed the meridian (i.e.
reached transit) two hours ago, while a star with HA = -1 will be on the
meridian in one hour. An HA of 23 hours is equivalent to HA = -1.
- To find the HA of a star we must know the current position of the
zero point of RA, the vernal equinox. This is given by the
sidereal time or ST. ST is defined to be the hour angle of
the vernal equinox, and it is the fundamental measure of astronomical
time of day. By this definition, ST is also equal to the RA
of an object now on the meridian.
- At a given ST, the HA of a star with a given RA is:
- Sidereal time runs faster than the mean solar time that
our watches use by 3 minutes and 56 seconds per day, a result of the
Earth's orbital motion around the sun. This means that the sidereal
time at a given standard time changes continuously by 2 hours per
month (or 24 hours in a year). If the ST at 9 PM EST tonight is
6 hours, one month from now it will be 8 hours. A table listing the
ST at 9 PM EST throughout the year is given in the Appendix to the 130
Manual.
- Using the HA/DEC system and an equatorially-mounted telescope,
you can quickly locate objects in the sky if your know their RA, DEC,
and the sidereal time. One problem: HA changes continuously, so when
you predict HA, you need to allow time to set the telescope.
- You must know both HA and DEC to determine visibility (refer to
the diagram at the start of this section).
An object with HA = +6 hours (-6 hours) is just setting (rising) on
the horizon if it lies on the celestial equator (with DEC = 0); it
will be visible in the sky for almost 12 hours a night. Objects south
of the equator will be visible for fewer hours. Objects north of the
equator will be visible for more hours. Any object in the circumpolar
region is above the horizon all the time (from HA = 0 to 24), but
cannot be seen in the daytime because of scattered light from the
Sun.
Altitude & Meridian Slice
- The HA/DEC system is part of the celestial Equatorial Coordinate
System defined with respect to the poles and equator. However, it is
often useful also to know how to locate an object with respect to your
horizon plane.
- Altitude is defined to be the angle between a star
and your horizon plane. In general, you need to use trigonometry to
find the altitude of an object with a given HA and DEC.
- However, when the star is on the meridian, there is a simple
relation between its DEC, your latitude, and its altitude. This is
illustrated in the figure above, which shows a geometric "slice"
through your local meridian.
- Based on the diagram, the altitude of a star above the southern
horizon (SALT in the diagram above) is given by the following
expression, where LAT is your latitude.
- LAT = 38o at Charlottesville, so here SALT = DEC +
52o.
- Objects with DEC = LAT have altitudes of
90o, i.e. they cross through your zenith. The celestial
equator (DEC = 0) has SALT = (90o - LAT).
- SALT is a useful concept for determining how high in the sky a
planet or the Moon, for instance, can be on a given night.
- As an example, the Moon orbits in a plane which is tilted
5o from the plane of the ecliptic. Since the maximum
DEC of the Sun (or the ecliptic) is +23.5o, the maximum
DEC of the Moon is +28.5o. The maximum altitude
of the Moon above the southern horizon is then:
SALT = 28.5o + (90o - 38o) =
80.5o.
Homework:
- Read Appendices A and B in the ASTR 130 Manual
- Consult reference material in Norton's Star Atlas, as
needed
- A set of sample questions & problems concerning the material
covered in the lectures will be available later this week. These will
not be graded, but you should work through these in preparation for the
Midterm Exam.
- You should complete the Constellation Quiz ASAP and move on this
week to Labs 2 and 3.
Related Web links:
Last modified
4 February 2001 by rwo
Star trail image copyright © David Malin/Anglo Australian
Observatory. Zodiac and axis tilt drawings copyright © by Nick Strobel. Other
professional drawings copyright © 1974,5 by Edmund Scientific
Corp. Other material copyright © 1998-2001 Robert W. O'Connell.
All rights reserved. These notes are intended for the private,
noncommercial use of students enrolled in Astronomy 130 at the
University of Virginia.