| 1 : Preliminaries | 6 : Dynamics I | 11 : Star Formation | 16 : Cosmology |
| 2 : Morphology | 7 : Ellipticals | 12 : Interactions | 17 : Structure Growth |
| 3 : Surveys | 8 : Dynamics II | 13 : Groups & Clusters | 18 : Galaxy Formation |
| 4 : Lum. Functions | 9 : Gas & Dust | 14 : Nuclei & BHs | 19 : Reionization & IGM |
| 5 : Spirals | 10 : Populations | 15 : AGNs & Quasars | 20 : Dark Matter |
|
|
5 km s-1 Mpc-1

= 0.73
0.02 : dark energy dominates the current universe
DM = 0.26
0.02 : dark matter is very important, particularly in structure formation
b = 0.04
0.01 : baryons are a trace (though vital!) component
= 5.0 × 10-5 : CMB photons reveal an early hot phase
= 3.4 × 10-5 : CNB neutrinos are predicted, but have not yet been observed
"The Concordance Model"
we are living through (and participating in!) a historic period of intellectual growth
in the future, our time will be recalled much like that of Copernicus, Newton, or Darwin.
The subject is now mature and sophisticated -- much is well beyond our/my range
Our aim will be to outline the overall framework, while ignoring details
(b) The Cosmological Principle
The Universe looks, statistically, the same from all locations
go to any galaxy -- you will witness an istotropic universe.
in addition to uniformity, it explicitly states the universe does not evolve
we won't consider the Steady State cosmology further.
all locations are (statistically) equivalent (e.g. have the same mean density)
Far from being bizarrely remote; the distant Universe would be remarkably familiar.
d
10% uncertainty in the gradient, Ho (see below)
5 km/s/Mpc (72 × 10-6 Myr-1 in psm units)
" [Topic 1.3k]
galaxy redshifts have two components:
galaxies appear to move radially away from us suggesting we are somehow central
Consider two (vector) locations k and p and the vector field: v = H r centered on us (at O)
We see p move at vp = H p; so how does an observer located on k see p move?
use primes to denote values measured by k [image]:
p' = p - k and v'p = vp - vk = Hp - Hk = H(p - k) = Hp'
if we see v = Hr then so does everyone else!
the cosmological principle still holds true
the Universe itself is undergoing isotropic expansion with form v = H r
This is a remarkable and profound result.
current age.
a ballpark figure for the age of the Universe.
In this case, you can relax: the time we've introduced is a proper time
it is measured by inertial observers, and can be agreed upon by everyone.
fundamental observers may synchronize clocks when the local density reaches some value
since these observers are at rest w.r.t. their local frame, they measure proper time
=
), we have cosmic time:
we can all agree on the age of the universe, and the time/age at a given redshift: t(z).
hence the entire sky should shine with the surface brightness of stars!(Absorption doesn't help: dust ultimately heats to reach equilibrium with the radiation field).
L ~ 108 LB,
Mpc-3 with M/L ~ 10 [Topic 4.3]
L ~ 10-32 erg s-1 cm-3; n
~ 108 Mpc-3; 
~ 10-31 gm cm-3 (

~ 0.01); 
~ R
2


~ 1018 Mpc : a typical sight line terminates at an enormous distance.
L r2 d
dr / 4
r2 =
LD/4
erg s-1 cm-2 sr-1
µ ~ 24m arcsec-2 ie very dark!
L ~ 0.07 LV,
pc-3 for the MW disk, requires
D ~ 109 Mpc to reach Olbers' bright sky.
Clearly, given its current emptiness, a dark sky only rules out gigantic old static Universes.
L ~ 10-32 erg s-1 cm-3 it would take them 1026 years !
A bright sky requires our static universe to be both gigantic and immensely old.
crit c2 ~ 10-8 erg cm-3, well below what is needed
rad ~ 109 !
Stars alone cannot yield Olbers' bright sky, even in an old enough and big enough Universe.
For this light source, then, it is expansion which keeps the sky dark.
If Olbers had lived in the first 500 kyr, when the Universe was in LTE, there would be no paradox!
(a) Expanding Coordinate Grids
for a set of i points, cosmic expansion gives: ri(t) = a(t) ri(to), for a fiducial time to
Finding the form for a(t) is a holy grail in cosmology.
For example, at the time of recombination, a
0.001
The comoving distance to proto-M87 is still 15 Mpc, but its physical distance is only 15 kpc.
Later we introduce several pseudo-distances: eg luminosity &
angular diameter distance; DL, DA.
these are not true (proper) distances, but convenient functions of distance.
In these notes I will try to be consistent: r = physical; ro = comoving; D = pseudo.
dr/dt = v(t) = da/dt × r(to) = (1/a) da/dt r(t)
But this is simply: v(t) = H(t) r(t) with H(t) = (1/a) da/dt
we have found that the Hubble relation applies at all times
H(a) H(t) =  1/a da/dt
and dr/dt = v = H r
|
Ho and it has units of inverse time
obs/
em; and cz rather than v(z) is sometimes taken as a "Doppler velocity"
it arises from expansion of space, not motion through space.
we will never see them!
| rH,o = c/Ho is called the Hubble distance; where, right now, galaxies recede at c |
For constant rate of expansion, we will ultimately see everything inside a sphere of radius rH,o
Only if v slows down significantly will we be able see beyond rH,o.
These, and other potentially confusing things, should become clearer later [sec 7].
o / e =
1 + z = a(to) / a(te)   = 1 / a(te)
|
since the current scale factor a(to) = 1
This is a fundamental relation & globally exact
It tells us the relative change in size since the light set out
Some examples:
a(te) = 1/1.1 = 0.909
90%
A nice observation verifies that the redshift is indeed caused by expansion:
If a distant event has true duration 
, the object is
v
further away at the end of the event
The light therefore arrives v
/c late and we observe a duration
t = 
+ v
/c
(1 + z)

This is called cosmological time dilation (a detailed analysis changes
to = )
It has been observationally verified: distant SNIa have slower light curves by 1+z [image L 5.6]
(i) Ladder Method
In elementary texts, the distance ladder is often presented with many rungs [image]
In practice, there are really only three:
calibrate Period-Luminosity (PL) relation
25 Mpc) galaxies
calibrate Tully-Fisher (TF) & Fundamental-Plane (FP) (& other) methods
group mean redshifts & distances now give Ho
This class of pulsating stars defines a tight period-luminosity(-color) relation [images]
measure period to get luminosity and hence distance
they are luminous stars (M: -8 to -12?) and hence can be seen to considerable distances (~25 Mpc by HST)
however, they are also rare: so there are only ?? within ??pc, which tend to be of low luminosity.
Historically, the PL relation was calibrated by Main Sequence fitting to open clusters containing Cepheids
Now, Hipparcos provides direct trigonometric calibration (eg Perryman et al 1997)
however, this calibration still needs to be improved (eg using future astrometric missions SIM, GAIA).
The distance to the LMC plays a very important role (and also still needs to be improved)
it contains enough Cepheids to define the PL relation in m (not M)
hence extragalactic Cepheids yield relative distances to the LMC
the current best estimate for the LMC is: m-M = 18.50
0.13
50
3.2 kpc (uses E(B-V) = 0.1)
the HST Key Project has now measured ~?? Cepheids in ~?? galaxies out to ~25 Mpc.
These galaxies were then used to calibrate the following methods:
This is a luminosity-linewidth relation for spirals [Topic 5.4b]
scatter is minimum in the near IR (I, H), hence the method is often referred to as "IRTF"
about 20 spirals now have Cepheid distances
about 25 groups/clusters out to 10,000 km/s have TF distances
Ho = 71
8
(eg Sakai et al 1999)
This is a refinement of the luminosity-linewidth (Faber-Jackson) relation for ellipticals
[Topic 7.4b]
Either Dn-
(isophotal diameter/dispersion) or surface
brightness/radius/dispersion relations
since no Cepheids in Es, calibration uses Es in groups with Cepheid distances (eg Virgo, Fornax, Leo)
many groups/clusters out to 10,000 km/s now have FP distances
Ho = 78
10
(eg Mould et al 1996; Kelson et al 1999)
These are very luminous, so well suited to qo studies (high z), but also useful for Ho (lower z)
the light curves aren't all the same; but peak luminosity correlates with fading rate (and color) [image]
unfortunately, very few SNIa have ocurred in galaxies with Cepheid distances
calibration not ideal
Ho = 68
6
(eg Gibson et al 1999)
Consider a set of CCD pixels recording the light from an E galaxy, each one with perfect S/N ratio
there is still variation between the pixels because of
N fluctuations in # stars
Although the mean surface brightness is independent of distance, the variation is not
nearer galaxies have fewer stars per pix
larger variation.
difficulties: contamination by globular clusters; color/population dependency; calibration.
HST can use this method out to about 7000 km/s
Ho = 69
7
(eg Ferrarese et al 1999)
Ho = 72
5?
km s-1 Mpc-1 (eg Friedman et al 2002?) [image]
This method applies to all pulsating/expanding photospheres -- particularly Type II (core collapse) SN
angular size is derived from flux, temperature and emissivity (black body = 1)
linear size is derived from integrating velocity (linewidth) over time
distance, by comparing angular and linear sizes.
Fortunately (!), EPM distances agree, statistically, with Cepheid distances
EPM distances now available for SN II out to 14,000 km/s (check)
Ho = 73
11
(eg Schmidt et al 1994)
So far, only one good example of this method exists: NGC 4258, Miyoshi et al 1995 [ Topic 13.4e]
a compact (~1pc) molecular disk orbits central black hole
VLBI of H2O masers gives (Keplerian) velocities and proper motions
distance, by comparing linear and angular velocities (??
?? Mpc)
this method has good potential for future (more distant) objects (eg at z > 0.5 it would give Ho and qo).
2 QSO images have different light paths with different physical lengths
this path difference is given by the time delay between QSOs light curved (via cross-correlation).
the calculated path difference depends on projected mass density and linear scale
distance by comparing observed angular scale and calculated linear scale
About 10 now done
Ho - 60 - 65 (puzzlingly low).
Hot electrons in galaxy cluster ICMs do two things:
ne2 rc3 Tx1/2
T/T)CMB
ne rc Tx
you can solve for rc and compare with
c to get a distance
Ho = 60 - 65
(eg Birkinshaw 1998) also puzzlingly low.
Why do the more distant (lensing & SZ) methods seem to give systematically low values for Ho?
Perhaps we live in a void with higher local Ho than the global value?
The answer is "probably not", for several reasons:
The local value is probably within a few percent of the global value.
Why the more distant estimates seem to yield low values is not yet understood.
5 km s-1 Mpc-1
Spergel et al (2003) used this HST Key Project value for their WMAP concordance model.
Many people now adopt this as the (currently) favoured value.
[images: D1.6; D1.5; OU7.2]
also need to say whether virgoflow infall corrections are used or not...

and p are both additive:
tot = 
i and ptot =
pi
)
and p vary, using local conservation of energy + the EOS.
plays its role
G/3)a2
= -kc2/R0
-ve Etot
closed
geometry (bound system)
+ve Etot
open
geometry (unbound system)
zero Etot
flat
geometry
c which yields a flat geometry (k=0):
(1/a2)(da/dt)2 = H2 = (8 G/3) c giving
c = 3H2/(8 G)
|
c = 2.65 × 10-7 h2 M
pc-3
= 1.80 × 10-29 h2 gm cm-3 = 10.8 h2 mp m-3
c varies with time through H(t) (or h), and we'll write its current value as
c,o
if
o =
c,o now, then
=
c always (worth stressing, since this seems to be the case).
c using
/
c
| Component | / c,o |
w | x = -3(1+w) ax |
x = 2/(3+3w) a tx |
1 + 3w sign accel |
| Dark Energy | 0.73 | -1 | 0 | a et |
-2 |
| Dark Matter | 0.23 | 0 |
-3 | 2/3 | 1 |
| Baryons | 0.04 | 0 |
-3 | 2/3 | 1 |
| Photons | 5.0 × 10-5 | 1/3 | -4 | 1/2 | 2 |
| Neutrinos | 3.4 × 10-5 | 1/3 | -4 | 1/2 | 2 |
tot =
i = 1.00
0.02
we live in a universe with "flat" spatial geometry
This is one of the most important discoveries in recent cosmology.
tot
as defining the future of the Universe, it doesn't.
= 0), when it was common to state:
tot > 1, the Universe will turn around, collapse, and end in a big crunch.
tot < 1, the Universe will expand forever.
0, one cannot infer
the future simply from
tot.
tot only fixes the spatial geometry (open/flat/closed), not the future.
frame dragging.
In slightly more technical terms:
Einstein's Gµ
= -8
G/c2 Tµ
states: space-time geometry = energy-momentum distribution.
the µ
indices are 0,1,2,3 (ct,x,y,z), and T0,0 alone covers the energy (including rest mass)
the other three components are for momentum of which pressures are a form
kT/µ
contains both rest mass and energy
c2
= w c2 (true for relativistic & non-rel. fluids)
1 keeps sub-luminal sound speed: cs < c
(w = 1 refers to "stiff matter", with cs = c)
|p|
w
1
| w = 0 | this is called "dust" (for historical reasons), matter with zero pressure. |
w 0 | non-relativistic matter (present day baryons, CDM) |
| w = 1/3 | relativistic matter (photons, neutrinos) |
| w = -1 | vacuum energy (the cosmological constant is also described by w = -1) |

- 1) and its pressure p = (
- 1) u = nkT
is closer to 1 when particles themselves store internal, rot/vib, energy)
= 5/3 with u = 3/2 nkT and p = nkT
= 9/7 with u = 7/2 nkT and p = nkT
Let's quickly recover pV
= const. and
w
0 for our perfect (non-relativistic) gas
Consider U = uV and adiabatic expansion dQ = 0 = dU + p dV, so that dU = -pdV.
Multiply p = (
- 1) u by V to get pV = (
- 1) U, and then differentiate:
pdV + V dp = dU(
- 1) = -pdV(
- 1)
dp/p = -
dV/V
pV
= const
p = nkT and 3/2 kT = ½ m<v2> so using (rest) density
o we have
p = (
o/m) (m <v2>/3)
p =
oc2 × <v2>/3c2 so w = <v2>/3c2
0 for a non-relativistic gas.
0 = 0 and
= 4/3, so
-1 = 1/3 and we find:
- 1) u = 1/3 u = 1/3 (
c2 -
0c2) = 1/3
c2
w = 1/3 as we had before.
vc2 dV = -p dV
p = -
vc2
w = -1
Basically, you must provide energy to create more vacuum; ie do work to increase the volume
Normally, of course, gas does work on the surroundings, reducing its internal energy.
  (loitering model)
M ~ 0.3 but inflation suggests
tot = 1
M -
v < 0
.
have w=-1
vacuum energy is currently favoured (which can be treated as a
term)
vc2 = m4/(hc)3 for "natural mass" m
vc2 ~ 3 × 10126 eV cm-3
(~1093 gm cm-3 !!)
vc2 ~ 103 eV cm-3, or ~10123 × smaller; maybe the worst guess ever.
DM = 0.23
0.04
b
cold dark matter (CDM)
clusters efficiently
b = 0.044
0.005
m = jX × (M/L)X in band X [Topic 1.3j]
2.0 × 108 h L
,B Mpc-3
(
9 Watt AU-3)
crit we have (M/L)crit = 1400 h (M/L)
,B
7 million kg/Watt (very dark!)
m = 0.27
crit we have (M/L)m = 375
close to some clusters
b = 0.04
crit we have (M/L)b = 55
significantly more than most galaxies
on average, ~7000 tonnes/Watt.
~ 410 cm-3, and energy density, u
~ 0.26 eV cm-3.
) or 1.9 mm (B
)
0.002 K = 0.07%) [image]
5 k4/15h3c3 = 4
/c is the radiation constant and NOT the scale factor].
| Energy density | u = a T4 = 7.56 × 10-15 T4 erg cm-3 ucmb = 4.17 × 10-13 erg cm-3 = 0.26 eV cm-3 |
| Energy flux | J = uc/4 = caT4/4 = T4/ = 1.80 × 10-5 T4 erg s-1 cm-2 sr-1 Jcmb = 9.94 × 10-4 erg s-1 cm-2 sr-1 |
| Number density | n = a T3/2.7kB = 20.3 T3 cm-3 ncmb = 410 cm-3 |
| Number flux | N = nc/4 = 4.84 × 1010 cm-2 s-1 sr-1Ncmb = 9.78 × 1011 cm-2 s-1 sr-1 |
e
µ 
, each with particle/anti-particle pairs
six in all.
Cosmic Neutrino Background (CNB) similar to, but much younger than, the CMB
c2 (
0?) at decoupling, they were relativistic
"hot" dark matter.
= 4/3; w = 1/3) similar to the CMB.
decoupling the e+e- pairs annihilate (at kT ~ 0.5 MeV)
T
> T
= (11/4)1/3 T
giving T
= 1.94 K
,tot = 0.68 u
,tot = 9/11 n
= 335 cm-3 (currently)
's and
's (after e+e- annihilation) is:
urel = 1.68 u
= 1.68 a T
4
is:
rel = 
+ 
= 8.4 × 10-5 (today)
= 1.67 × 10-4 eV, so
only neutrino masses larger than this change things
= m
(eV) / 94 h-2
tot = 1 and close the Universe.
is small.
a-3
(1 + z)3 ie, densities drop as the volume increases.
p = p/c2), we must include this too.
a3
c2
and equation of state p/c2 = w
Consider conservation of energy: dQ = dU + pdV = 0 (since adiabatic)
d(
c2a3) = -p d(a3)
c2a3 d
+ 3
c2a3 da = -3pa2 da
d
/da = (-3/a)(
+ p/c2) = -3(1 + w)
/a which has solution:
=
0 a-3(1+w) = (1 + z)3(1+w) where once again we set a0 = a(t0) = 1
| matter: | m(a) = m,o a-3 = m,o (1 + z)3 | as expected by "conservation of mass" |
| radiation: | r(a) = r,o a-4 = r,o (1 + z)4 | since n a-3 and E a-1 from redshift
|
| vacuum: | v(a) = v,o = const | space is space |
m increases quickly, but not as quickly as
r
radiation dominates over matter at earlier times
Since
v is constant while the other densities are increasing
the vacuum rapidly becomes irrelevant and one can ignore it for the first Gyr or so.
More generally, the component with most positive w dominates at early times (radiation)
the component with most negative w dominates at late times (vacuum) [images]
| density match | condition | a @ equality | z @ equality | t @ equality |
v = m |
0.73 = 0.27 a-3 | 0.72 | 0.39 | 9.43 Gyr |
v = rel |
0.73 = 8.4 × 10-5 a-4 | 0.103 | 8.3 | 615 Myr |
b = ![]() |
0.04 a-3 = 5.0 × 10-5 a-4 | 1.25 × 10-3 | 800 | 620 kyr |
m = rel |
0.27 a-3 = 8.4 × 10-5 a-4 | 3.11 × 10-4 | 3200 | 57 kyr |
m = ![]() |
0.27 a-3 = 5.0 × 10-5 a-4 | 1.85 × 10-4 | 5400 | 22 kyr |
Note that here
rel refers to the sum of photons and neutrinos (relativistic matter)
Likewise
m refers to the sum of baryons and CDM (non-relativistic matter)
o =
c,o and
=
o a-3(1+w), we have
G/3)a2
= (8
G/3)a2
o a-3(1+w) = Ho2
o/
c,o a-3(1+w) = Ho2 a-(1+3w)
da/dt = Ho a-(1+3w)/2
a(1+3w)/2
da = Ho
dt
a =
[(3 + 3w)/2 . t/tH]2/(3+3w)
| during the radiation era: | a t1/2 |
| during the matter era: | a t2/3 |
| during the vacuum era: | a et (from da/dt a) |
2
= -4
G
In General Relativity, a similar relation gives the acceleration:
G (
+ 3p/c2) = -(4/3)
G
(1 + 3w)
, but it includes a pressure term.
(1 + 3w), then
if w < -1/3 we find that gravity is repulsive!
0.1.
.
v is +ve and adds to gravity, while pv is -ve and dominates, giving net acceleration.
internal energy decreases
internal energy increases
vc2 behaves the same way
An extreme example: imagine a strange piston with a little "strange water" in it.
You pull extremely hard, with force F = p x A, with p = 9 x 1020 dyne cm-2 (~1015 atm) and A = 1 cm2
the piston slowly moves out by d = 1 cm -- you have spent F x d = 9 x 1020 erg of energy.
To your surprise, the piston now contains an additional cm3 of water!
Your 9 x 1020 erg were converted to
9 x 1020/c2 = 1 gm of new water.
(Note: since dark energy is 6.8 x 10-30 gm cm-3, it only requires 6 x 10-9 dyne cm-2 tension to create.
However, you can't verify this experimentally because there is vacuum on both
sides of the piston!).
For normal matter, expansion spreads mass out, raising
the gravitational energy
The loss of energy to the gravitational field comes out of the kinetic energy of expansion -- it decelerates
For radiation, the situation is even worse, since expansion affects both M and R in
the gravitational term.
But for vacuum, the M2 term beats out the R term, and the gravitational
energy is more negative
(one detail: this only becomes true for regions larger than the Hubble volume).
The whole thing is not unlike a ball falling downwards:
by moving down, R is smaller, so Ugrav is more negative.
to conserve energy, the ball must pick up positive kinetic energy, and hence it accelerates.
For a vacuum dominated universe, a larger universe has more negative binding
energy (G M2/R increases)
Some of this gravitational energy is used to make the additional vacuum.
Where does the rest go? Into the kinetic energy -- the fluid accelerates
Thus, a vacuum dominated universe "falls downwards" by expanding and accelerating.
o:
o) d
o = (8
/c3)
o2 [exp(h
o/kTo) - 1]-1 d
o
1, the corresponding frequency is
=
o / a, giving d
= d
o / a
) d
=
n(
o) / a3 d
o
) d
=
(8
/c3)
2 a2[exp(h
a/kTo) - 1]-1 a d
, giving
) d
=
(8
/c3)
2 [exp(h
/kToa-1) - 1]-1 d
| T = To / a = To (1 + z) |
systems:
< v2 >, while for BB: T
<
>
=
o / a, ie v = vo / a
dv/v = -da/a with solution:
a-1 or, for v = vo at a = 1, we have v = vo/a
as time passes a increases & v decreases; hence random motions decrease and T drops
No vo2 (m/2
kTo)3/2 exp(-mvo2 / kTo) dvo (N and n in number per cm3)
at time when a
1, we have v = vo/a and dv = dvo/a
particle conservation also requires n(v)dv = n(vo)/a3 dvo and N = No/a3
Substituting these into the MB relation, we get:
a3N a2v2 (m/2
kTo)3/2 exp(-mv2a2 / kTo) a dv
N v2 (m/2
k(To/a2))3/2 exp(-mv2 / k(To/a2)) a dv
| T = To / a2 = To (1 + z)2 |
a-2
a-1
At z ~ 1100 both have T
3000K; at z = 0, T
2.725 K, while Tmatter
2.48 mK.
In practice, this cooling for the baryonic gas never occurs:
= -8
G/c2
Tµ
& Tµ
are both 4 × 4 matricies, suggesting 16 equations, though symmetries reduce this to 10.
= 0,1,2,3 denote 1 time & 3 space coordinates (e.g. ct, x, y, z or ct, r,
,
).
= 0), and momentum
(µ,
= 1,2,3) in the system
Loosely speaking, this section looks at the geometry part, G.
The next section looks at the dynamical part, T, and how it relates to G.
r2; a sphere has area 4
r2 and volume 4/3
r3
Adding Newton's intuitively plausible independent time, t, yields a 4 coordinate space-time
2 where ds2
(ds)2, etc.
ds2 = dx2 + dy2 + dz2 = dr2 + r2 (d
2 +
sin2
d
2)
= dr2 + r2 d
2
Note that the choice of cartesian or polar (or any other) coordinate system is unimportant
They are equivalent and define the same space.
ds) to construct a triangle
its interior angles sum to 180o; and so on.
from a pole, where r is measured along the surface [image]
2
2)
2 contribution to ds2.
ang =
+ A/R2
any measured triangle allows you to obtain the radius of curvature, R
for the sphere, all triangles give the same R: the space is homogeneous and isotropic
the sphere has finite circumference (2
R) and finite surface area (4
R2).
2 where d
2 = d
2 + sin2
d
2, r is
a "straight" line from origin.
To get a feel for the odd nature of this space, imagine holding a laser pointer with visible beam (r)
Turn it through 1o (d
= 1o):
)
/2 the sweep begins to decrease for larger r
R.
If you explored geometry living in this kind of space, you would not recover the Euclidean results
In 1840 Gauss actually tried to measure the curvature of space by surveying big triangles [image].
Of course, his modestly accurate measurements only recovered the Euclidean value of 180o
But in principle he could have discovered the non-Euclidean terrestrial Schwarzschild metric.
(in fact, R ~ 1AU, and a 30 km triangle deviates from 180o by ~10-8 arcsec).
R) and volume (2
2R3)
ang =
- A/R2 which is less than 180o
ds2 = -c2 dt2 + dr2 + r2 (d
ds2 = -c2 dt2 + dr2 + R2 sinh2(r/R) (d
One can also replace (d
As you can see, the three metrics above are all of this kind: as r
Of course, the second derivatives do not vanish, and it is these that define the
curvature.
Light moves along special null geodesics, so named because ds = cd
We can also use a freely moving object to define a "straight line".
Curvature
k
d
2
coefficient Parallel
Lines Triangle
Angles Sphere
Area Sphere
Volume Global
Form
Positive
+1
R2 sin2(r/R)
Converge
> 180
< 4
r2 < (4/3)
r2 Closed
Flat
0
r2
Never meet
180
4
r2 (4/3)
r2 Open
Negative
-1
R2 sinh2(r/R)
Diverge
< 180
> 4
r2 > (4/3)
r2 Open
(iv) Adding Time
The 3-D + 1-t metrics for positive, flat, and negative space-times become:
ds2 = -c2 dt2 + dr2 + R2 sin2(r/R) (d
2 + sin2
d
2)
2 +
sin2
d
2)
(Minkowski space-time).
2 + sin2
d
2)
2 +
sin2
d
2) with
d
2, the angle between the two events on the sky,
and group them into a single expression, using Sk(x) = sin(x), x, sinh(x) for k = +1, 0, -1:
ds2 = -c2 dt2 + dr2 + R2 Sk2(r/R) d
[ Note: I've adopted Peacock's notation for Sk, rather than Ryden's ]
2
-c2d
2, where d
is the Lorentz invariant proper time interval.
Indeed, the second is the spacetime of special relativity, and is called Minkowski spacetime.
flat geometry is rooted in the Pythagoraean relation (e.g. triangles have
ang = 180o).
Although more general geometries are curved, many are locally flat (e.g. in 3-D: a sphere)
expanding the metric to first order at any location gives a quadratic form.
Such geometries are called Reimannian and the spacetimes of GR are all of this kind. Why?
Because locally the Equivalence Principle demands a Minkowski spacetime of Special Relativity.
0, they are locally flat.
Physically, these give tidal forces which are apparent across regions of finite size.
(v) Geodesics
because straight lines are the shortest distance between two points.
E.g. on the 2-D surface of a sphere, geodesics are great circles
(hence: "aphrodisiacs" are great circles passing through Africa, ho ho).
it's minimum energy state would occupy the shortest distance.
Fermat's principle ensures they take the path of least time
the shortest path
this occurs because longer paths interfere destructively (cf Feynman's little book: QED).
Recall Newton's 1st law:
"objects free from external forces remain at rest or in uniform motion in a straight line"
(its wavefunction behaves just like the light waves: longer paths interfere destructively).
= 0 (light never feels time)
Recall, in GR gravity is not a force; instead mass curves space, and objects "follow" the space
Einstein's version of Newton's 1st law becomes:
free falling objects move along "straight lines" (geodesics) in the curved 4-D space-time.
e.g. Earth's orbit is curved in 3-space, but follows a geodesic in the 4-D space-time near the sun.
These form a diverging non-intersecting bundle with common origin in the big bang.
(This is known as Weyl's postulate (1923), and it ensures a legitimate cosmic proper time).
In practice, this means we only see things which lie on our past light cone
(a light cone is a conic surface in a 3-D spacetime, in which the 4th space axis is omitted)
World lines need not be geodesics; for example if they are acted on by a force.
you, for example, held up by the earth's surface, follow a world line, not a geodesic.
Conversely, geodesics are all world lines: the path through space-time of a freely falling object.
On large scales (> few Mpc): these assumptions are excellent [see sec 2a-c]
On intermediate scales, where |
/<
>| < 1 they are still useful:
On small scales, where 
/<
> >> 1 they are poor assumptions:
ds2 = -c2 dt2 + a(t)2 [ dro2 + Ro2 Sk2(ro/Ro) d 2 ]
|
where ro is the comoving proper distance (ie as measured today) to an object.
This looks very familiar!
1/Ro2) .
coefficient
Please don't think of R(t) as "the radius of the universe"; it is a measure of spatial curvature
although for k = +1 it yields roughly the correct total volume, for k = -1 it is negative.
Also, the limiting condition near k = 0 with R
is well behaved, since R sin(r/R)
r.
it comes just from requiring isotropy & homogeneity at all times.
= 0 and so ds = -c2d
2 = -c2dt2 giving t = 
= 0, and "at time t" means dt = 0, so the RW-metric gives
ds = a(t) dro and the total proper distance is r =
ds =
a(t) dro = a(t)
dro = a(t) ro
= 0 and ds = 0
c dt/a = dro
c dt/a =
dro = ro which is constant
Two photons are emitted at te and te +
te and arrive
at times to and to +
to
During the time te +
te to to both photons are in flight and so
dt/a for this interval is the same.
But for the full trip
dt/a is also the same, so the small start/finish contributions must be equal:
te / a(te) =
to / a(to)
to /
te =
a(to) / a(te) = 1 / a(te) (since a(to)
1)
This tells us that the duration of any event we witness is dilated by a factor
a(te)-1
A heuristic explanation of this dilation (simiar to a normal Doppler effect) was given
in [sec 3e]
As mentioned there, the dilation has been seen in the lengthened light curves of high-z supernovae
te and
to to be the time between wavecrests of light, we have the cosmological redshift:
to /
te =
e /
o =
o /
e = (1 + z) = a(te)-1
Once again, it is best to think of redshift as a change in scale factor during the photon's journey.
(v) Total Cosmic Volume
only sweeps out a distance: a(t) Ro sin(ro/Ro) d
a(t) Ro sin(ro/Ro), and the full area is: 4
a(t)2 Ro2 sin2(ro/Ro)
a(t) Ro
a(t)2 Ro2
sin2(ro/Ro) dr = 2
2 a(t)3 Ro3
as expected, the volume grows with a(t)3 and is close to the value for a 2-sphere of radius R
for an open universe the integral diverges because (i) the area diverges, and (ii) r
= 8
G/c2 Tµ
: spacetime is curved by the distribution of cosmic
energy & momentum.
It is now time to introduce GR so we can derive expressions for a(t), Ro and k
Fortunately (for you and me) the treatment will be heuristic, brief, and goal oriented.
vector
tensor.
2
= -4
G
q:
2 V = -
q /
o
(c2
2 -
2 /
t2) Aµ = -jµ /
o
q while j1,2,3 are the x, y, z currents
mo
This second aspect undermines a vector treatment, and a tensor treatment is
necessary.
Instead of a 4-vector mass/momentum current, we need a 4 × 4 mass/momentum matrix
Of course, relativistically "mass" is superceeded by energy and we speak of
Tµ
:
the "energy-momentum" tensor (or "stress-energy" tensor).
Here, µ and
are four (1 time, 3 space) coordinate indices, (eg ct, x, y, z; or ct, r,
,
)
has 4 × 4 = 16 elements, arranged in a square.
is diagonal.
c2 is the total energy density
T1,1, T2,2, T3,3 = < pxpx >c2 / E is the x-momentum density
px the x-pressure (y, z etc)
Now, pressure is isotropic, so px = py = pz = p (don't confuse momentum p with pressure p)
So Tµ
= diag (
c2, p, p, p) (all off-diagonal elements are zero).
(iii) Gµv : The Curvature Tensor
, what about Gµ
?
2 in the Newtonian Poisson equation).
,
,
with 44 = 256 elements.
, and its scaler trace, the Ricci curvature, R.
= Rµ
- ½ gµ
R where gµ
are the metric coefficients]
the geometry is Reimannian.
is diagonalEvaluating the elements for the RW-spacetime, one obtains:
G1,1 = G2,2 = G3,3 = -1/a2 [ 2 a (d2a/dt2) + k c2/Ro2 + (da/dt)2]
to the same elements of Tµ
& add the proportionality constant:
G
= 8
G/c2 T0,0
Gj,j =
-1/a2 [ 2 a (d2a/dt2) + k c2/Ro2 + (da/dt)2] = 8
G p/c2 = 8
G/c2 Tj,j
Combining these, we arrive at two fundamentally important cosmic equations
(da/dt)2 = (8 G/3) a2 - k c2/Ro2 | The Friedmann Equation, or Energy Equation |
d2a/dt2 = -(4 G/3) a ( + 3p/c2) | The Acceleration Equation |
where k = +1, 0, -1 follows the sign of the curvature radius Ro; and a(t) is the scale factor.
/dt = -3/a da/dt (
+ 3p/c2) now divide by da/dt, insert p = w
c2 and rearrange:
1/3(1 + w) × d
/
= da / a which integrates to give:
=
o a-3(1 + w) with
=
o at a = 1
(a) can now be inserted in the Friedmann equation, which then yields a(t)
You will recall deriving
(a) in [sec 4e] using conservation of energy dU = -pdV
Einstein's equations implicitly contain energy conservation, which therefore also provide
(a)
Of course, it helps to choose an equation of state, p = w
c2, of particularly simple form.
(v) A Newtonian Analog
Consider a huge sphere uniformly but sparsely filled with rubble (technically: "dust") [image]
Focus on a single rock at radius ro: it feels only interior mass: M =
4/3
ro3
o
To follow the rock's motion, define radial coordinate r = a(t) ro (track using a scale factor)
Set the whole sphere expanding, with dr/dt = ro da/dt for our rock.
Finally (see below) assume the whole sphere expands uniformly, maintaining uniform density.
in this case the mass interior to our rock is constant: and M = 4/3
r3
where E
is the rock's energy at r
This is just the equation for throwing a stone vertically upwards:
if E
> 0, then v > vesc and the rock escapes; if E
< 0, then v < vesc and the rock returns.
Rewriting this equation using the changing scale factor and density, we get:
G/3)
a2 + E
/ ro2
/ ro2 standing in for -curvature: -k c2/Ro2
G/3)
r
G/3)
a
This would be identical to the GR equation if
were replaced by (
+ 3p/c2).
Newton, obviously, misses the fully relativistic energy and pressure contributions to gravity.
= ½vo2 - GM/ro =
½ Ho2 ro2 - 8/3
G ro2
o
Inserting E
back into the Friedmann equation and cancelling the ro2 terms we get:
(da/dt)2 = (8
G/3)
a2 + ½(Ho2 - 8/3
G
o)
which implies the following:
G
o or critical density
c = 3Ho2 / 8
G
For PE, we just perform the standard integration for the PE of a uniform density sphere:
(4/3)
r3
× 4
r2
× r-1 dr = - (3/5) GM2/R, for R = outer radius.
The KE we also get by integrating over the Hubble law, and substituing for H2 = 8
G
/3:
4
r2
(Hr)2 dr = (3/5) GM2/R
Hence, the total energy of the sphere began and remains zero throughout.
Later [sec 7d] we find a similar energy conservation result if we take R to be the horizon distance.
denser patches expand more slowly than average so the density contrast increases
these ultimately act as mini closed universes, and collapse to make stars & galaxies.
,
c =
3H2 / 8
G (varies with time)
c,o =
3Ho2 / 8
G = 1.37 × 10-7 M
pc-3
=
/
c =
(8
G/3H2)
(vary with time)
m,o =
m,o /
c,o =
(8
G/3Ho2)
m,o
t   =
m   +
r   +
v
t   =
m   +
r   +
v (all these vary with time)
t(a) / c,o = m,o a-3   + r,o a-4   + v,o
|
This is an exceedingly important relation:
it gives the full density evolution as a function of a or z using today's measured values.
[warning:
t(a) /
c,o is not the evolving density parameter,
t(a)
t(a) /
c , see sec 6cvii]
(iii) Curvature Parameters: Ro &
k
(1/a2)(da/dt)2 = H2 = (8
G/3)
- kc2/a2Ro2
substitute for
= 3H2
t / 8
G to get
H2 = H2
t - kc2 / a2Ro2 which yields:
t,o - 1) ] ½ [notice k (
t,o - 1) is always positive]
This is as expected: Ro
for
t,o
1
Current estimates put
t,o -1 < 0.02, so Ro > 7 c/Ho = 30 Gpc.
At earlier times, R = a Ro is smaller.
k
-kc2/R2H2 =
-kc2/a2Ro2H2
and
k,o
-k c2/Ro2Ho2
Inserting into the Friedmann equation we find: H2 = H2
t + H2
k
1 =
t +
k
which is simply our Newtonian energy identity, normalized to KE:
KE = PE + E
[Notice,
k and k have opposite sign: +ve
k means open geometry]
k allows us to recast the Friedmann equation in compact and soluble(!) form [sec 6ci] :
t(a)/
c,o
+
k,o a-2 ] = Ho2
[
m,oa-3 +
r,oa-4 +
v,o +
k,oa-2 ]
where k,o is simply 1 - t,o = 1 - ( m,o + r,o + v,o)
|
k,o and the Hubble distance rH,o = c / Ho :
Ro = rH,o / | k,o | ½
|
To find an expression for this, start with the acceleration equation & divide by a:
1/a (d2a/dt2) = -H2 q   =
-(4
G/3) (
+ 3p/c2)
= -(4
G/3)
(1 + 3w)
G/3H2) (3H2/8
G)
(1 + 3w) =
½
(1 + 3w)
q = ½ [
m + 
2
r - 2
m ] = ½
m  +
r -
v at any time, or
qo = ½ m,o  + r,o - v,o today.
|
v cosmology days (1970s-90s), this was always +ve, with qo = ½
o (
r,o is negligible)
m and
v
m = 0.26 and
v = 0.73, we have qo = -0.6 : we are accelerating.

:
= Rµ
- ½R gµ
+
gµ
G/3)
a2 - k c2/Ro2 + 1/3
a2
d2a/dt2 = -(4
G/3) a (
+ 3p/c2) + 1/3
a
and p:
in terms of
v, and discovering that w = -1:
= 8 G v = 3 H2 v   (units of time-2)
and v = -pv/c2 (i.e. w = -1)
|
basically, derive those expansion/contraction
graphs we've seen since high school.
The form of a(t) depends on two things:
t
(a), which depends on the fluid.
Let's begin with the general case, then look at some special cases.
(i) The General Case
's [sec 6biii]:
| 1/a2(da/dt)2 |
= (8 G/3)
- (1/a2) kc2/Ro2 |
= Ho2
(8 G/3Ho2) + (1/a2) Ho2 k,o |
|
= Ho2 [ / c,o + k,o a-2 ] |
|
= Ho2 [ m,o a-3 + r,o a-4 + v,o + k,o a-2 ] |
|
| = Ho2 E2(a) which gives: |
| 1/a (da/dt) = H(a) = Ho E(a) for the evolution of the Hubble parameter |
where we use Peeble's notation for E(a) [or E(z)], and the curvature "density"
k,o :
E(a) [ m,o a-3 + r,o a-4 + v,o + k,o
a-2 ] 1/2 |
E(z) [ m,o (1+z)3 + r,o (1+z)4 + v,o + k,o (1+z)2 ] 1/2 |
k,o 1 - t,o = 1 - m,o - r,o - v,o
|
These are exceedingly important functions, and are central to all cosmological calculations.
Notice that they involve current (hence observable) values of
, and so can be evaluated directly.
da / a E(a) = Ho
dt   =   Ho t (da from 0 to a; dt from 0 to t)
In general, this and related integrals need to be done numerically
Since E(a) and its integral are often needed, it's good to have a working subroutine handy.
(IDL, Mathematica, Matlab all have ready integrators; as does Numerical Recipes, eg qromb).
where tH,o = 1 / Ho is the Hubble time; one can also use the Hubble radius c dt = rH,o da / aE(a) etc.
Let's now look at the time evolution of some specific FRW world models.
Integrating the general relation gives a current age 0.988 tH,o and a(t)
curve shown here: [image]
Taken individually, these yield reasonable approximations for a(t) over most
of cosmic history.
Two details:
These recover the forms from [sec 4f]: a
a E(a) = [a-(1+3w)]½
you can quickly check this gives 1 & 2 above, for w = 0 and 1/3.
Here I chose to use tH in place of tH,o since the relation for tage is true at all times.
Note that w = -1/3 separates ac-/de-celerating models, and hence tage greater/less than tH,o
tage = (2/3) tH,o
which recovers an age conveniently close to tH,o There is, however, a more compelling reason: they are crucial in theories of galaxy formation
This has a parametric solution which uses a "development angle",
which turns at a(
where apar =
For a closed geometry, additional possibilities include (see below):
Ages and futures for all these models can be nicely seen in these plots
[image]
you can move between them with the following important relations between their differentials:
dt = tH,o da / aE(a) = -tH,o dz / (1+z)E(z) along with da = -dz/(1+z)2 = -a2dz
For example, the relation for current cosmic age is simply:
dt (0 to now) = -tH,o
dz / (1+z)E(z)   (
to 0) = tH,o
da / aE(a)   (0 to 1)
(ii) The Concordance Model
v,o = 0.73;
m,o = 0.27;
r,o
= 8.4 × 10-5;
t,o = 1.00 (
k,o = 1 -
t,o = 0)
during the radiation era: E(a)
r,o½ a-2
during the matter era: E(a)
m,o½ a-3/2
during the dark energy era: E(a)
v,o½
This [ image ] shows the
approximations and their errors, while the table gives the functional forms.
[The Toolbox includes a more
extensive set, including Hubble radius, particle and event horizons.]
Approximations to the Concordance model
Radiation era: E(a)
r,o½ a-2
t = tH,o
da / a E(a) (0 to a)
½ tH,o
r,o-½ a2
741 a2 h72-1 Gyr = 2.34 x 1019 a2 h72-1 sec
a
1.16 x 10-6 h72½ tyr½
2.09 x 10-10 h72½ ts½
Matter era: E(a)
m,o½ a-3/2
t = tH,o
da / a E(a) (0 to a)
2/3 tH,o
m,o-½ a3/2
17.4 a3/2 h72-1 Gyr
a
1.49 x 10-7 h722/3 tyr2/3
Dark Energy Era: E(a)
v,o½
t - tnow =
t = tH,o
da / a E(a) (1 to a)
tH,o
v,o-½ ln(a)
15.9 ln(a) h72-1 Gyr
a
exp[
tGyr h72 / 15.9 ] (tnow = 0.988 tH,o)
Formally, the exponential term has infinite past, so it is sensible
to integrate from a=1, the current time.
The matter solution is improved slightly by adding 39,000 years
to correct the integral over the radiation era.
In our Newtonian analog [sec 6av]: how does the rock's
speed change after the initial throw?
To find this, we simply use the Hubble relation:
v = H r = H a ro = da/dt ro = Ho a E(a) ro
By choosing ro = 1 Mpc, we get the velocity history for a galaxy now at 1Mpc
notice the minimum at a
0.65 when
m,o
v,o and we change from de- to ac-celeration
notice also the ever increasing velocity as t
0, a feature of all non-zero
m or
r models
The initial expansion is essentially infinitely fast, with a(t) curves all starting out vertical
This parallels the Newtonian case where v
vesc = (GM/r)1/2
as R
0.
For the universe, v(a) increases even faster since radiation dominates giving v
a-1 as a
0.
H(a) gives the velocity at 1 Mpc real distance, not 1 Mpc comoving distance
Thus, H(a) increases even more quickly as a
0.
They also illustrate the behaviour of the various "eras" in the multi-component models.
da / aE(a) (from 0 to a); with E(a) containing just one term:
1. Pure matter:
m,o= 1; a E(a) = [a-1]½ t = (2/3) tH,o a3/2 a = [3/2 t/tH,o]2/3
2. Pure radiation:
r,o= 1; a E(a) = [a-2]½ t = (1/2) tH,o a2 a = [2 t/tH,o]1/2
3. Pure vacuum:
v,o= 1; a E(a) = [a2]½ t - to = tH,o loge a a = e[(t - to)/tH,o]
4. Pure curvature:
k,o= 1; a E(a) = [
k,o]½ t = tH,o a a = t / tH,o
t2/3 , t1/2 , et for matter, radiation, vacuum.
The pure curvature model is open (not flat), with simple linear expansion at all times.
Pure matter & curvature models are also called: Einstein-de Sitter & Milne [sec 6cvi]
Note: the coefficients are different from the concordance approximations
because the current
's aren't unity.
t = 2/(3+3w) tH,o a(3+3w)/2
a = [ (3 + 3w)/2 (t / tH,o) ]2/(3+3w)
Note also that the flat model with w = -1/3 behaves like an open pure curvature (Milne) model.
tage = 2/(3 + 3w) tH
2/3 tH , 1/2 tH ,
, tH for 1 - 4 above.
As we suspected from the outset, tage
tH to within factors ~unity.
The exception is pure vacuum, with exponential expansion and infinite age (t
-
as a
0)
For example, for flat matter (Einstein-de Sitter; w = 0) we have tage = 2/3 tH,o, a famous result.
By including a component with w < -1/3 (eg vacuum/lambda), then tage can get longer than tH,o
This was a key motivation for including
to solve tH,o < t
(1930s), or tH,o < tGC (1990s).
(v) Flat Models: Matter + Vacuum
m and
v
Apart from a brief (~50 kyr) radiation period, this is basically the Universe we live in.
a(t) = (
m,o /
v,o)1/3 sinh2/3 [ (3/2)
v,o1/2 (t / tH,o) ] = 0.712 × sinh2/3 (1.28 × t / tH,o)
v,o-1/2 sinh-1 [ (
v,o /
m,o)1/2 ] = 0.78 × 1.27 tH = 0.993 tH,o
Ho-1
i.e. the decelerating & accelerating portions "average out" to approximate a constant expansion.
(the numbers here use:
v,o = 1 -
m,o = 0.73)
(vi) Curved Models: Matter Only
open with infinite future; closed ending in a big crunch; or "critical", balanced between the two
while the real Universe seems to be globally flat, this is not true locally:
voids form from open regions; while stars/galaxies/clusters form from closed regions
FRW curved matter models apply since local evolution is independent of the surroundings.
s =
s,o a-3(1+w) and
a E(a) = [
s,o a-(1+3w) + (1 -
s,o)]1/2
For w = 0 (matter) we have t(a) = tH,o
[
m,o a-1 + 1 -
m,o ] -1/2 da (from 0 to a)

The form of the solution depends on whether
m,o > 1 (closed) or
m,o < 1 (open):
= 0 to 2
, the Universe expands, halts, and recollapses in a cycloid:
a(
) = ½ amax (1 - cos
)
t(
) = ½ tH amax (
- sin
) / (
m,o - 1)1/2
) = amax =
m,o / (
m,o - 1) and collapses at t(2
) =
tH,o amax / (
m,o - 1)1/2
for example, if
m,o = 1.5, we have amax = 3 and tcrunch = 6.7 tH,o
= 0 to 
a(
) = ½ apar ( cosh
- 1)
t(
) = ½ tH,o apar ( sinh
-
) / (1 -
m,o)1/2
m,o / (1 -
m,o) plays the role of amax
m,o = 0.9, 0.0, 1.1) are shown here [BR 6.1]
(vii) Specific & Named World Models
k -ve), flat
(k = 0,
k = 0), open (k = -1,
k +ve)
v: -ve (odd), 0 (simplest), +ve (what seems to be true).
This is because radiation quickly becomes irrelevant when
r <
m at t ~
50 kyr.
negative
: unusual; simply adds to matter; all models recollapse
zero
: most discussed until recently; all decelerate; future depends only on curvature.
closed recollapses; flat halts @
positive
; open expands forever.
Examples for
m = 0.9, 1.0, 1.1 are shown [here, L7.6; BR 6.1]
: early, matter dominates
decelerates; late, vacuum dominates
accelerates.
For
v <
v,E
both collapse and "bounce" solutions exist
For
v
v,E vacuum repulsion and closed geometry nearly balance
long ~static periods.
Ironically, neither Einstein nor de Sitter advocated this.
et; infinite past; H(a) = const
This model has renewed importance, since it is believed to occur during inflation.
It also describes the Steady State model, which needs H(a) = const.
pre-dated Hubble's discovery of expansion; doesn't fit above analysis since Ho = 0.
Instead, set da/dt = d2a/dt2 = 0 to find balance when:
m+
v -1 = 3/2 (
v
m2)1/3
The model is unstable to small deviations from balance.
Infinitely long static history before starting expansion
big bang in remote past, then expansion comes to gradual halt at infinite future.
v (
m) slightly below (above) the critical values.
Big bang
expansion
"loitering"
exponential expansion.
The motivation for loitering was the too short (incorrect) Hubble time, tH,o = Ho-1
The age can be increased by introducing
; see this example: [images]
Lemaitre preciently also wanted a big bang to make elements
k = +1, open, (k = -1).
Similar to
m/r/v << 1
no de- ac-celeration: linear expansion a = t / tH; tage = tH
Milne's (incorrect) motivation: moving galaxies subject only to special relativity.
| Hubble time: tH,o = Ho-1 = 10.0 h-1 Gyr = 13.9 h72-1 Gyr |
| Hubble distance:   rH,o = c / Ho = c tH,o = 13.9 h72-1 G lyr = 4.26 h72-1 Gpc |
they are units comparable to the current age and visible size of the Universe.
r(to) = c dt / a(t) (te to to) = rH,o
da / a2 E(a) (a to 1) = rH,o
-dz / E(z) (z to 0)
|
Alternatively, from the RW metric: photons move on radial null geodesics, so d
= ds = 0, giving:
c2 dt2 = a2(t) dro2
c
dt / a(t) =
dr = r(to) (te to to and 0 to ro) as before.
LBT = (to - te) = dt (te to to) = tH,o da / a E(a) (a to 1); = tH,o -dz / (1+z) E(z) (z to 0)
|
Which are all straightforward to evaluate (numerically).
m,o = 1,
v,o =
k,o = 0)
-(1 + z)-3/2 dz (z to 0) = 2 rH,o [1 - 7-1/2] = 1.24 rH,o
r(te) = r(to) / (1 + z) = 1.24 rH,o / 7 = 0.18 rH,o
(to - te) = tH,o
-(1 + z)-5/2 dz (z to 0) = 2/3 tH,o [1 - 7-3/2] = 0.63 tH,o
The QSO was 0.18 rH,o when the light set out; it is now 1.24 rH,o; the light travelled for 0.63 tH,o.
r(te) = 1.94 rH,o / 1001 = 0.0019 rH,o or only ~ 8 Mpc!
tot = 1.0
we are in a spatially infinite Universe.
| rH(a) = rH,o / E(a) = rH,o / E(z) |
or, re-expressing rH(a) in its larger current comoving size, ro,H(a), we have:
| ro,H(a) = rH(a) / a = rH,o / a E(a) = rH,o (1 + z) / E(z) |
In physical coordinates, rH increases from zero at t = a = 0 (z =
) and continues to increase.
In comoving coordinates, ro,H grows/shrinks in de/ac-celerating universes.
0.61 rH,o
m =
v at a = 0.72, when ro,H = 1.15 rH,o
4.9 Gpc
to 0):
rp-hor(to) = c dt / a(t) (0 to to) = rH,o da / [a2E(a)] (0 to 1)
= rH,o -dz / E(z) ( to 0)
|
m or
r, the integral is finite, and there is indeed a most
distant object visible.
-(1 + z)-3/2 dz (
to 0) = 2 rH,o
Using the concordance values in E(z) gives rp-hor = 2.55 rH,o = 10.9 h72-1 Gpc (35.5 Gly)
m or
r, all locations expand with infinite speed [sec 6cii]
Only if the initial expansion is zero can light cross everywhere in the first instant.
This occurs in two FRW cases:
rp-hor(t) = c dt / a(t) (0 to t) = rH,o da / a2E(a) (0 to a)
= rH,o -dz / E(z) ( to z)
|
Giving 2 a1/2 rH,o for Einstein-de Sitter; a rH,o for flat radiation;
for flat vacuum (de Sitter)
(t)
dt / a(t) (0 to t)
da / a2E(a) (0 to a)
-dz / E(z) (
to z).
This is a useful surrogate for time, in part because it gives the horizon size at a given t, a, z.
It is the time variable of choice for studying growth of perturbations.
Space-time diagrams (see below) can also look much simpler when plotted using conformal time.
(iii) The Event Horizon: re-hor (furthest ultimately visible)
re-hor(t) = c dt / a(t) (t to ) = rH,o da / a2E(a) (a to ) = rH,o -dz / E(z) (z to -1) |
Which is the same as rp-hor but with different (complementary) integration ranges
Not surprisingly, if an FRW model has finite rp-hor it often has infinite
re-hor, and visa-versa
Einstein-de Sitter & flat radiation have re-hor =
; while flat vacuum (de Sitter) has rH,o /2a2
Vacuum in the concordance model ensures we will never see remote parts of the Universe.
Indeed, as time passes, we will see less and less as the event horizon shrinks (in comoving radius).
It also plays a crucial role generating and amplifying quantum fluctations.
Ultimately, these fluctations provide the seeds for future galaxy formation [sec 11].
Such diagrams are more complex on curved expanding space-times in cosmological GR:
It is, however, often possible to clean up these diagrams & reestablish 45o light paths:
(t)   = conformal time
=
o a-3(1+w),
Ignoring these concerns (!), we proceed to estimate the total energy within a Hubble sphere: rH = c / H.
Our aim is merely to suggest that the Universe's total energy might actually be ZERO
= 3 H2 / 8
G and velocity law v = H r :
PE = -(3/5) GM2/R = -(3/20) R5 H4 / G
KE = ½
4
r2dr
(H r)2 = +(3/20) R5 H4 / G
and we recover the Newtonian result: Etot = PE + KE = E
= 0 for all R.
R3
c2 = (1/2) R3 H2 c2 / G =
(1/2) R3 rH2 H4 / G
Hence: |PE| / RE
(R / rH)2 so that on small scales rest mass utterly dominates cosmic energy.
However, when R
rH the -ve gravitational energy grows to match the +ve rest mass energy.
e.g. for R ~ rH,o we have RE ~ |PE| ~ rH,o5 Ho4 / G = c5 / Ho G
1076 erg
1022 M
1011 Mgal
This crudely illustrates how on cosmic scales the total energy, including rest mass, could be zero.
| Everything may have arisen from Nothing |
All matter in the Universe is borrowed against the negative gravitational energy of space-time.
the mass of a black hole can be found entirely in the energy of its gravitational field.In the cosmic context, the Hubble radius provides a kind of Schwarzchild/gravitational radius :
RS = 2GMH / c2 = 2G(4/3)
rH3
/ c2 = 2G(4/3)
(c3/H3) 3H2 / 8
G / c2 = c / H = rH
how does this affect the simple Euclidean relationships?
With these in mind we can derive close analogs to the Euclidean relationships.
Indeed, one usually expresses them in Euclidean form, using a pseudo-distance, D, in place of r.
The most famous of these are luminosity distance, DL, and angular diameter distance, DA
I'll try to keep the convention of labelling pseudo-distances with capital D.
d2
dz / E(z) (z to 0), the current proper distance
d2 for closed (open) geometries.
2 + sin2
d
2)
Integrating over
and
for the total spherical shell area, we get:
Ro2 Sk2(ro/Ro) =
4
D(ro)2 [ where D(ro)  
Ro Sk(ro/Ro) ]
D(ro) is a comoving distance measure and is our first pseudo-distance:
think of a × D as giving the correct d
if we placed physical area dA at proper distance a × ro
D2
f = L / 4 D2 ×
1 / (1 + z)2 = L / 4 DL2 [ where DL (1 + z) D ]
|
DL is the luminosity distance and is our second pseudo distance
it gives the correct (bolometric) luminosity using the Euclidean formula.
| D(ro) = Ro Sk(ro/Ro) | effective angular comoving distance |
ro(z) = rH,o -dz / E(z) (from z to 0) |
true comoving proper distance |
| Sk(x) = sin(x)   x   sinh(x) (k = +1 0 -1) | corrects for curvature |
Ro = rH,o / | k,o | ½ |
the curvature radius [sec 6b iii] |
k,o = 1 - t,o |
the curvature parameter |
Notice that for k = 0, D = ro and apart from the (1 + z)-2 term, we recover the Euclidean relation.
Likewise, for ro << Ro and z << 1, we recover the full Euclidean relation.
Here is a figure showing DL(z) for several world models [image]
= L
/ 4
DL2 × [ L
(
(1 + z)-1) / L
(
) ] × (1 + z)-1 (units: erg/s/cm2/A)
f
= L
/ 4
DL2 × [ L
(
(1 + z)) / L
(
) ] × (1 + z) (units: erg/s/cm2/Hz)
f
=
(1 + z)-1 L
(
(1 + z)-1) / 4
DL2 (units: erg/s/cm2)
f
=
(1 + z) L
(
(1 + z)) / 4
DL2 (units: erg/s/cm2)
Usually, continuum fluxes require these relations, while emission lines are bolometric.
= ds / d
= d
= dt = 0)
,
the RW-metric gives:
= a(te) D(ro) d
= D(ro) / (1 + z) d
note a(te) is included since the light ray geodesics start at emission time, te [image R&T 6.1]
d = ds / a(te) D = ds / DA [ where DA D / (1 + z) = DL / (1 + z)2 ]
|
DA is the angular diameter distance and is our third pseudo distance
it gives the correct angular diameter using the Euclidean formula.
place galaxies further away: they first look smaller, then stay the same, then look bigger!
A comoving (ie current) size dS was smaller at redshift z: ds = dS/(1 + z).
Using this in the relation d
= ds / DA we get:
d = dS/(1 + z) / [D/(1 + z)] = dS/D
= dS/DEA [ where DEA D ]
|
DEA = D is the angular diameter distance for an object expanding with the Hubble flow.
Let's do our example of 100 Mpc at z = 0.2, 5, 1000, choosing Einstein-de Sitter (flat, matter):
for this, we have D = ro = rH,o
dz / (1 + z)3/2 = 2 dH,o [1 - (1 + z)-½] = [0.17, 1.18, 1.94] × rH,o
Using rH,o = 4.26 Gpc, we have d
= 7.9o, 1.14o, 0.69o for z = 0.2, 5, 1000.
These angular sizes don't get bigger at high z, because our object was smaller back then.
Notice that our supercluster is ~8o in the SDSS, it is still ~1o at z = 5 and ~0.7o on the CMB
d /dt = ds/DA / dt' (1 + z) = vt / D = vt / DM [ where DM D ]
|
DM = D is the proper motion distance, and is seen to be our original pseudo distance, D
it gives the correct transverse velocity from a proper motion, assuming the Euclidean relation
This is the appropriate distance to use when measuring projected jet speeds in radio galaxies.
(note, David Hogg's classic "cheat sheet" uses DM, DC and DH for my D, ro and rH,o)
)2 =
L/(4
d2) / (s/d)2 = L / 4
s2 (independent of d)
Moving to the RW-metric: f decreases
(1 + z)-2, and (d
)2 increases
(1 + z)2
SB = f / (d )2 =
L/(4 DL2) / (s/DA)2 = L / 4 s2 (1 + z)-4
|
This is the (almost) equally famous (1 + z)-4 rapid drop in surface brightness with redshift.
note it is independent of curvature and, of course, is Euclidean at low-z.
(1 + z)-3, and SB
(1 + z)-5
The proper comoving area at comoving distance ro is A(ro) = d
D2, where D = RoSk(ro/Ro).
The proper comoving volume of a shell of depth dro is dVC = A(ro) dro = d
D2 dro
Now, since ro = rH,o
dz/E(z), then we have
dro = rH,o dz/E(z) which gives:
rH,o D2 dz/E(z), which can be integrated between redshifts:
VC(z1 to z2) = d rH,o -D(z)2 dz/E(z) (from z1 to z2)
|
-dz/E(z)   (z to 0)
The total (d
= 4
) comoving volume out to redshift z turns out to be:
rH,o3/
k,o [ D/rH,o(1 +
k,oD2/rH,o2)½ -
|
k,o |-½ ASk(
k,o½ D/rH,o) ]
D3 for k = 0
a2 D2
rH,o D2 (1 + z)-3 dz/ E(z) = dVC (1 + z)-3First some auxiliary functions & definitions we'll need:
m,o (1 + z)3 +
r,o (1 + z)4 +
v,o +
k,o (1 + z)2 ] 1/2
k,o = 1 - (
m,o +
r,o +
v,o) = 1 -
t,o
D = Ro Sk(ro/Ro) with Sk(x) = sin(x) ; x ; sinh(x) for k = +1 ; 0 ; -1
Ro = rH,o / |
k,o |½ with rH,o = c/Ho = c tH,o
dro = c dt / a = rH,o dz / E(z) = rH,o da / a2E(a)
dt/ a   [te to to] =
rH,o
-dz/ E(z)   [z to 0] =
rH,o
da/ a2E(a)   [a to 1]
dt   [te to to] =
tH,o
-dz/ (1 + z)E(z)   [z to 0] =
tH,o
da/ a E(a)   [a to 1]
ro,H(z) = c / aH(z) = rH,o (1 + z) / E(z)
dt/ a   [0 to t] =
rH,o
-dz/ E(z)   [
to z] =
rH,o
da/ a2E(a)   [0 to a]
dt/ a   [t to
] =
rH,o
-dz/ E(z)   [z to -1] =
rH,o
da/ a2E(a)   [a to
]
DL2 DL = D(1 + z) is the luminosity distance
= S / DA DA = D/(1 + z) is the angular diameter distance
c = Sc / D
for an object expanding with the universe, with comoving size Sc
:
D2 dro = d
D2 rH,o dz/ E(z)
dV = dVc × (1 + z)-3 is the physical (non-comoving) volume in the same shell
Yes, these did take me a long time to make.
On the limits of extragalactic astronomy, so this will be brief
dm,o,
b,o,
r,o,
v,o wv plus a few others
one needs good "standard candles" or "standard rulers", as we shall see.
Some useful figures: [images]
The Primary Cosmological Parameters
Measuring Mean Component Densities
Number Counts
Luminosity Distance Measurements
Angular Diameter Measurements
The Structure Parameters
The CMB Power Spectrum
The Concordance Model
Future Work
The Flatness Problem
The Horizon Problem
The Structure Problem
The Antimatter Problem
The Entropy Problem
The Existance Problem
k.
This framwork manages to account for an extremely wide range of observations,
It also provides several independent estimates of its basic parameters .
Apart from the unknown nature of dark matter & energy, the framwork seems quite robust.
why was the expansion launched exactly
the way it needed to be to yield our current universe?
whatever its radius, this rock always has the same mass, M, beneath it.
= -GM/rturn and
½vesc2 = GM/rin
Hence, ½ vin2 = GM (1/rin - 1/rturn) giving (vin/vesc)2 = (1/rin - 1/rturn) / (1/rin)
1 - rin/rturn
So, in order to reach rturn, it must start within
v of vesc where:
v / vesc
½ rin/rturn
As rin gets smaller and smaller, the initial velocity must get closer and closer to vesc.
This is the Newtonian analog of the "flatness problem":
in order to get so BIG, the Universe must have been launched incredibly close to vesc.
~ 1 km, where vesc ~ 850 km/s (<
>
106 tonnes cm-3)
t,o, is within 5% of unity
(equivalently,
k,o < 0.05).
t,o =
t,o /
c,o
= 8
G
t,o / 3Ho2
t,o - 1 = -
k,o = kc2/Ro2Ho2 [see sec 6b iii]
t(a) = 8
G
t / 3H2, where H and
t are now both functions of a.
t /
c,o =
m,oa-3 +
r,oa-4 +
v,o = E2(a) -
k,oa-2
t(a) = 8
G
c,o (
t /
c,o) / 3Ho2E2(a) = [ E2(a) -
k,oa-2] / E2(a) =
1 -
k,o / a2E2(a)
which is the relation we need.
m,oa-1 +
r,oa-2 +
v,oa2 +
k,o
k,o
0) we find going backwards in time (ie a
0),
t
1 ,
k
0 , as long as either matter or radiation dominates.
t(a) = 1 - k,o / a2E2(a) =
1 - k,o / [ v(a) / vo]2 |
giving a simple rule:
Hence, for the standard model, the Universe was flatter in the past, and will get flatter in the future
a2E(a)2
r,o / a2
and t = tH,o
da / a E(a) (0 to a)
½ tH,o
r,o-½ a2
2.33 x 1019 h72-1 a2 sec.
so the curvature becomes:
k(a)
k,o a2 / r,o
104 a2 k,o
5.0 x 10-16 tsec h72-1 k,o
|
k is only ~1% of the current value,
k,o ;
k
10-14
k,o ; and at the GUT era (a ~ 10-28)
k
10-52
k,o !Of course, inflation's early acceleration can generate just this kind of extreme flatness.
k
0 &
t
1),
0 as a
0 !
k depend differently on a.
k and
k,o which use R and Ro:
k = -kc2 / R2H2 = -kc2 / [ a2Ro2 Ho2E2(a) ] =
k,o / a2E2(a)
So R2H2 follows a2E2(a), and although R
0 as a
0, R × H increases and drives
k to 0.
Of course, a × H(a)
v(a), the velocity history (our previous result), and we have v
as a
0.
integrated over a Hubble sphere, the positive
mass-energy is balanced by an equal negative gravitational energy
what mechanism can start with nothing,
and create arbitrary amounts of matter and gravity?
c2/3.
G/3) a (
+ 3p/c2)
=
o a-3(1+w) and the Friedmann
energy equation gives:
G
/3)½ a = (8
G
o/3)½
a-(1 + 3w)/2 = Ho a-(1 + 3w)/2
which has solutions:
w > -1: a(t) = [(3 + 3w)/2 . t/tH]2/(3+3w)
power law expansion; index > 1 (acceleration) for -1 < w < -1/3.
w = -1: a(t) = a(to) e(t - to)/tH
pure exponential expansion, with e-folding time tH = H-1.
w < -1: a(t) = [1 + (3 + 3w)/2 . (t - tnow)/tH]2/(3+3w) big rip (a
) at
t = tnow + 2tH / |3+3w|.
The last two solutions have no clear big bang, ie a
0
only as t
-
-1, giving approximately exponential growth.
G
)½ = 1.34
6-½ sec (with
6 in units of 106 gm cm-3)