| 1 : Preliminaries | 6 : Dynamics I | 11 : Star Formation | 16 : Cosmology |
| 2 : Morphology | 7 : Ellipticals | 12 : Interactions | 17 : Structure Growth |
| 3 : Surveys | 8 : Dynamics II | 13 : Groups & Clusters | 18 : Galaxy Formation |
| 4 : Lum. Functions | 9 : Gas & Dust | 14 : Nuclei & BHs | 19 : Reionization & IGM |
| 5 : Spirals | 10 : Populations | 15 : AGNs & Quasars | 20 : Dark Matter |
|
|
5 km s-1 Mpc-1

= 0.73
0.02 : dark energy dominates the current universe
DM = 0.26
0.02 : dark matter is very important, particularly in structure formation
b = 0.04
0.01 : baryons are a trace (though vital!) component
= 5.0 × 10-5 : CMB photons reveal an early hot phase
= 3.4 × 10-5 : CNB neutrinos are predicted, but have not yet been observed
"The Concordance Model"
we are living through (and participating in!) a historic period of intellectual growth
in the future, our time will be recalled much like that of Copernicus, Newton, or Darwin.
The subject is now mature and sophisticated -- much is well beyond our/my range
Our aim will be to outline the overall framework, while ignoring details
(b) The Cosmological Principle
The Universe looks, statistically, the same from all locations
go to any galaxy -- you will witness an istotropic universe.
in addition to uniformity, it explicitly states the universe does not evolve
we won't consider the Steady State cosmology further.
all locations are (statistically) equivalent (e.g. have the same mean density)
Far from being bizarrely remote; the distant Universe would be remarkably familiar.
d
10% uncertainty in the gradient, Ho (see below)
5 km/s/Mpc (72 × 10-6 Myr-1 in psm units)
" [Topic 1.3k]
galaxy redshifts have two components:
galaxies appear to move radially away from us suggesting we are somehow central
Consider two (vector) locations k and p and the vector field: v = H r centered on us (at O)
We see p move at vp = H p; so how does an observer located on k see p move?
use primes to denote values measured by k [image]:
p' = p - k and v'p = vp - vk = Hp - Hk = H(p - k) = Hp'
if we see v = Hr then so does everyone else!
the cosmological principle still holds true
the Universe itself is undergoing isotropic expansion with form v = H r
This is a remarkable and profound result.
current age.
a ballpark figure for the age of the Universe.
In this case, you can relax: the time we've introduced is a proper time
it is measured by inertial observers, and can be agreed upon by everyone.
fundamental observers may synchronize clocks when the local density reaches some value
since these observers are at rest w.r.t. their local frame, they measure proper time
=
), we have cosmic time:
we can all agree on the age of the universe, and the time/age at a given redshift: t(z).
hence the entire sky should shine with the surface brightness of stars!(Absorption doesn't help: dust ultimately heats to reach equilibrium with the radiation field).
L ~ 108 LB,
Mpc-3 with M/L ~ 10 [Topic 4.3]
L ~ 10-32 erg s-1 cm-3; n
~ 108 Mpc-3; 
~ 10-31 gm cm-3 (

~ 0.01); 
~ R
2


~ 1018 Mpc : a typical sight line terminates at an enormous distance.
L r2 d
dr / 4
r2 =
LD/4
erg s-1 cm-2 sr-1
µ ~ 24m arcsec-2 ie very dark!
L ~ 0.07 LV,
pc-3 for the MW disk, requires
D ~ 109 Mpc to reach Olbers' bright sky.
Clearly, given its current emptiness, a dark sky only rules out gigantic old static Universes.
L ~ 10-32 erg s-1 cm-3 it would take them 1026 years !
A bright sky requires our static universe to be both gigantic and immensely old.
crit c2 ~ 10-8 erg cm-3, well below what is needed
rad ~ 109 !
Stars alone cannot yield Olbers' bright sky, even in an old enough and big enough Universe.
For this light source, then, it is expansion which keeps the sky dark.
If Olbers had lived in the first 500 kyr, when the Universe was in LTE, there would be no paradox!
(a) Expanding Coordinate Grids
for a set of i points, cosmic expansion gives: ri(t) = a(t) ri(to), for a fiducial time to
Finding the form for a(t) is a holy grail in cosmology.
For example, at the time of recombination, a
0.001
The comoving distance to proto-M87 is still 15 Mpc, but its physical distance is only 15 kpc.
Later we introduce several pseudo-distances: eg luminosity &
angular diameter distance; DL, DA.
these are not true (proper) distances, but convenient functions of distance.
In these notes I will try to be consistent: r = physical; ro = comoving; D = pseudo.
dr/dt = v(t) = da/dt × r(to) = (1/a) da/dt r(t)
But this is simply: v(t) = H(t) r(t) with H(t) = (1/a) da/dt
we have found that the Hubble relation applies at all times
H(a) H(t) =  1/a da/dt
and dr/dt = v = H r
|
Ho and it has units of inverse time
obs/
em; and cz rather than v(z) is sometimes taken as a "Doppler velocity"
it arises from expansion of space, not motion through space.
we will never see them!
| rH,o = c/Ho is called the Hubble distance; where, right now, galaxies recede at c |
For constant rate of expansion, we will ultimately see everything inside a sphere of radius rH,o
Only if v slows down significantly will we be able see beyond rH,o.
These, and other potentially confusing things, should become clearer later [sec 7].
o / e =
1 + z = a(to) / a(te)   = 1 / a(te)
|
since the current scale factor a(to) = 1
This is a fundamental relation & globally exact
It tells us the relative change in size since the light set out
Some examples:
a(te) = 1/1.1 = 0.909
90%
A nice observation verifies that the redshift is indeed caused by expansion:
If a distant event has true duration 
, the object is
v
further away at the end of the event
The light therefore arrives v
/c late and we observe a duration
t = 
+ v
/c
(1 + z)

This is called cosmological time dilation (a detailed analysis changes
to = )
It has been observationally verified: distant SNIa have slower light curves by 1+z [image L 5.6]
(i) Ladder Method
In elementary texts, the distance ladder is often presented with many rungs [image]
In practice, there are really only three:
calibrate Period-Luminosity (PL) relation
25 Mpc) galaxies
calibrate Tully-Fisher (TF) & Fundamental-Plane (FP) (& other) methods
group mean redshifts & distances now give Ho
This class of pulsating stars defines a tight period-luminosity(-color) relation [images]
measure period to get luminosity and hence distance
they are luminous stars (M: -8 to -12?) and hence can be seen to considerable distances (~25 Mpc by HST)
however, they are also rare: so there are only ?? within ??pc, which tend to be of low luminosity.
Historically, the PL relation was calibrated by Main Sequence fitting to open clusters containing Cepheids
Now, Hipparcos provides direct trigonometric calibration (eg Perryman et al 1997)
however, this calibration still needs to be improved (eg using future astrometric missions SIM, GAIA).
The distance to the LMC plays a very important role (and also still needs to be improved)
it contains enough Cepheids to define the PL relation in m (not M)
hence extragalactic Cepheids yield relative distances to the LMC
the current best estimate for the LMC is: m-M = 18.50
0.13
50
3.2 kpc (uses E(B-V) = 0.1)
the HST Key Project has now measured ~?? Cepheids in ~?? galaxies out to ~25 Mpc.
These galaxies were then used to calibrate the following methods:
This is a luminosity-linewidth relation for spirals [Topic 5.4b]
scatter is minimum in the near IR (I, H), hence the method is often referred to as "IRTF"
about 20 spirals now have Cepheid distances
about 25 groups/clusters out to 10,000 km/s have TF distances
Ho = 71
8
(eg Sakai et al 1999)
This is a refinement of the luminosity-linewidth (Faber-Jackson) relation for ellipticals
[Topic 7.4b]
Either Dn-
(isophotal diameter/dispersion) or surface
brightness/radius/dispersion relations
since no Cepheids in Es, calibration uses Es in groups with Cepheid distances (eg Virgo, Fornax, Leo)
many groups/clusters out to 10,000 km/s now have FP distances
Ho = 78
10
(eg Mould et al 1996; Kelson et al 1999)
These are very luminous, so well suited to qo studies (high z), but also useful for Ho (lower z)
the light curves aren't all the same; but peak luminosity correlates with fading rate (and color) [image]
unfortunately, very few SNIa have ocurred in galaxies with Cepheid distances
calibration not ideal
Ho = 68
6
(eg Gibson et al 1999)
Consider a set of CCD pixels recording the light from an E galaxy, each one with perfect S/N ratio
there is still variation between the pixels because of
N fluctuations in # stars
Although the mean surface brightness is independent of distance, the variation is not
nearer galaxies have fewer stars per pix
larger variation.
difficulties: contamination by globular clusters; color/population dependency; calibration.
HST can use this method out to about 7000 km/s
Ho = 69
7
(eg Ferrarese et al 1999)
Ho = 72
5?
km s-1 Mpc-1 (eg Friedman et al 2002?) [image]
This method applies to all pulsating/expanding photospheres -- particularly Type II (core collapse) SN
angular size is derived from flux, temperature and emissivity (black body = 1)
linear size is derived from integrating velocity (linewidth) over time
distance, by comparing angular and linear sizes.
Fortunately (!), EPM distances agree, statistically, with Cepheid distances
EPM distances now available for SN II out to 14,000 km/s (check)
Ho = 73
11
(eg Schmidt et al 1994)
So far, only one good example of this method exists: NGC 4258, Miyoshi et al 1995 [ Topic 13.4e]
a compact (~1pc) molecular disk orbits central black hole
VLBI of H2O masers gives (Keplerian) velocities and proper motions
distance, by comparing linear and angular velocities (??
?? Mpc)
this method has good potential for future (more distant) objects (eg at z > 0.5 it would give Ho and qo).
2 QSO images have different light paths with different physical lengths
this path difference is given by the time delay between QSOs light curved (via cross-correlation).
the calculated path difference depends on projected mass density and linear scale
distance by comparing observed angular scale and calculated linear scale
About 10 now done
Ho - 60 - 65 (puzzlingly low).
Hot electrons in galaxy cluster ICMs do two things:
ne2 rc3 Tx1/2
T/T)CMB
ne rc Tx
you can solve for rc and compare with
c to get a distance
Ho = 60 - 65
(eg Birkinshaw 1998) also puzzlingly low.
Why do the more distant (lensing & SZ) methods seem to give systematically low values for Ho?
Perhaps we live in a void with higher local Ho than the global value?
The answer is "probably not", for several reasons:
The local value is probably within a few percent of the global value.
Why the more distant estimates seem to yield low values is not yet understood.
5 km s-1 Mpc-1
Spergel et al (2003) used this HST Key Project value for their WMAP concordance model.
Many people now adopt this as the (currently) favoured value.
[images: D1.6; D1.5; OU7.2]
also need to say whether virgoflow infall corrections are used or not...

and p are both additive:
tot = 
i and ptot =
pi
)
and p vary, using local conservation of energy + the EOS.
plays its role
G/3)a2
= -kc2/R0
-ve Etot
closed
geometry (bound system)
+ve Etot
open
geometry (unbound system)
zero Etot
flat
geometry
c which yields a flat geometry (k=0):
(1/a2)(da/dt)2 = H2 = (8 G/3) c giving
c = 3H2/(8 G)
|
c = 2.65 × 10-7 h2 M
pc-3
= 1.80 × 10-29 h2 gm cm-3 = 10.8 h2 mp m-3
c varies with time through H(t) (or h), and we'll write its current value as
c,o
if
o =
c,o now, then
=
c always (worth stressing, since this seems to be the case).
c using
/
c
| Component | / c,o |
w | x = -3(1+w) ax |
x = 2/(3+3w) a tx |
1 + 3w sign accel |
| Dark Energy | 0.73 | -1 | 0 | a et |
-2 |
| Dark Matter | 0.23 | 0 |
-3 | 2/3 | 1 |
| Baryons | 0.04 | 0 |
-3 | 2/3 | 1 |
| Photons | 5.0 × 10-5 | 1/3 | -4 | 1/2 | 2 |
| Neutrinos | 3.4 × 10-5 | 1/3 | -4 | 1/2 | 2 |
tot =
i = 1.00
0.02
we live in a universe with "flat" spatial geometry
This is one of the most important discoveries in recent cosmology.
tot
as defining the future of the Universe, it doesn't.
= 0), when it was common to state:
tot > 1, the Universe will turn around, collapse, and end in a big crunch.
tot < 1, the Universe will expand forever.
0, one cannot infer
the future simply from
tot.
tot only fixes the spatial geometry (open/flat/closed), not the future.
frame dragging.
In slightly more technical terms:
Einstein's Gµ
= -8
G/c2 Tµ
states: space-time geometry = energy-momentum distribution.
the µ
indices are 0,1,2,3 (ct,x,y,z), and T0,0 alone covers the energy (including rest mass)
the other three components are for momentum of which pressures are a form
kT/µ
contains both rest mass and energy
c2
= w c2 (true for relativistic & non-rel. fluids)
1 keeps sub-luminal sound speed: cs < c
(w = 1 refers to "stiff matter", with cs = c)
|p|
w
1
| w = 0 | this is called "dust" (for historical reasons), matter with zero pressure. |
w 0 | non-relativistic matter (present day baryons, CDM) |
| w = 1/3 | relativistic matter (photons, neutrinos) |
| w = -1 | vacuum energy (the cosmological constant is also described by w = -1) |

- 1) and its pressure p = (
- 1) u = nkT
is closer to 1 when particles themselves store internal, rot/vib, energy)
= 5/3 with u = 3/2 nkT and p = nkT
= 9/7 with u = 7/2 nkT and p = nkT
Let's quickly recover pV
= const. and
w
0 for our perfect (non-relativistic) gas
Consider U = uV and adiabatic expansion dQ = 0 = dU + p dV, so that dU = -pdV.
Multiply p = (
- 1) u by V to get pV = (
- 1) U, and then differentiate:
pdV + V dp = dU(
- 1) = -pdV(
- 1)
dp/p = -
dV/V
pV
= const
p = nkT and 3/2 kT = ½ m<v2> so using (rest) density
o we have
p = (
o/m) (m <v2>/3)
p =
oc2 × <v2>/3c2 so w = <v2>/3c2
0 for a non-relativistic gas.
0 = 0 and
= 4/3, so
-1 = 1/3 and we find:
- 1) u = 1/3 u = 1/3 (
c2 -
0c2) = 1/3
c2
w = 1/3 as we had before.
vc2 dV = -p dV
p = -
vc2
w = -1
Basically, you must provide energy to create more vacuum; ie do work to increase the volume
Normally, of course, gas does work on the surroundings, reducing its internal energy.
  (loitering model)
M ~ 0.3 but inflation suggests
tot = 1
M -
v < 0
.
have w=-1
vacuum energy is currently favoured (which can be treated as a
term)
vc2 = m4/(hc)3 for "natural mass" m
vc2 ~ 3 × 10126 eV cm-3
(~1093 gm cm-3 !!)
vc2 ~ 103 eV cm-3, or ~10123 × smaller; maybe the worst guess ever.
DM = 0.23
0.04
b
cold dark matter (CDM)
clusters efficiently
b = 0.044
0.005
m = jX × (M/L)X in band X [Topic 1.3j]
2.0 × 108 h L
,B Mpc-3
(
9 Watt AU-3)
crit we have (M/L)crit = 1400 h (M/L)
,B
7 million kg/Watt (very dark!)
m = 0.27
crit we have (M/L)m = 375
close to some clusters
b = 0.04
crit we have (M/L)b = 55
significantly more than most galaxies
on average, ~7000 tonnes/Watt.
~ 410 cm-3, and energy density, u
~ 0.26 eV cm-3.
) or 1.9 mm (B
)
0.002 K = 0.07%) [image]
5 k4/15h3c3 = 4
/c is the radiation constant and NOT the scale factor].
| Energy density | u = a T4 = 7.56 × 10-15 T4 erg cm-3 ucmb = 4.17 × 10-13 erg cm-3 = 0.26 eV cm-3 |
| Energy flux | J = uc/4 = caT4/4 = T4/ = 1.80 × 10-5 T4 erg s-1 cm-2 sr-1 Jcmb = 9.94 × 10-4 erg s-1 cm-2 sr-1 |
| Number density | n = a T3/2.7kB = 20.3 T3 cm-3 ncmb = 410 cm-3 |
| Number flux | N = nc/4 = 4.84 × 1010 cm-2 s-1 sr-1Ncmb = 9.78 × 1011 cm-2 s-1 sr-1 |
e
µ 
, each with particle/anti-particle pairs
six in all.
Cosmic Neutrino Background (CNB) similar to, but much younger than, the CMB
c2 (
0?) at decoupling, they were relativistic
"hot" dark matter.
= 4/3; w = 1/3) similar to the CMB.
decoupling the e+e- pairs annihilate (at kT ~ 0.5 MeV)
T
> T
= (11/4)1/3 T
giving T
= 1.94 K
,tot = 0.68 u
,tot = 9/11 n
= 335 cm-3 (currently)
's and
's (after e+e- annihilation) is:
urel = 1.68 u
= 1.68 a T
4
is:
rel = 
+ 
= 8.4 × 10-5 (today)
= 1.67 × 10-4 eV, so
only neutrino masses larger than this change things
= m
(eV) / 94 h-2
tot = 1 and close the Universe.
is small.
a-3
(1 + z)3 ie, densities drop as the volume increases.
p = p/c2), we must include this too.
a3
c2
and equation of state p/c2 = w
Consider conservation of energy: dQ = dU + pdV = 0 (since adiabatic)
d(
c2a3) = -p d(a3)
c2a3 d
+ 3
c2a3 da = -3pa2 da
d
/da = (-3/a)(
+ p/c2) = -3(1 + w)
/a which has solution:
=
0 a-3(1+w) = (1 + z)3(1+w) where once again we set a0 = a(t0) = 1
| matter: | m(a) = m,o a-3 = m,o (1 + z)3 | as expected by "conservation of mass" |
| radiation: | r(a) = r,o a-4 = r,o (1 + z)4 | since n a-3 and E a-1 from redshift
|
| vacuum: | v(a) = v,o = const | space is space |
m increases quickly, but not as quickly as
r
radiation dominates over matter at earlier times
Since
v is constant while the other densities are increasing
the vacuum rapidly becomes irrelevant and one can ignore it for the first Gyr or so.
More generally, the component with most positive w dominates at early times (radiation)
the component with most negative w dominates at late times (vacuum) [images]
| density match | condition | a @ equality | z @ equality | t @ equality |
v = m |
0.73 = 0.27 a-3 | 0.72 | 0.39 | 9.43 Gyr |
v = rel |
0.73 = 8.4 × 10-5 a-4 | 0.103 | 8.3 | 615 Myr |
b = ![]() |
0.04 a-3 = 5.0 × 10-5 a-4 | 1.25 × 10-3 | 800 | 620 kyr |
m = rel |
0.27 a-3 = 8.4 × 10-5 a-4 | 3.11 × 10-4 | 3200 | 57 kyr |
m = ![]() |
0.27 a-3 = 5.0 × 10-5 a-4 | 1.85 × 10-4 | 5400 | 22 kyr |
Note that here
rel refers to the sum of photons and neutrinos (relativistic matter)
Likewise
m refers to the sum of baryons and CDM (non-relativistic matter)
o =
c,o and
=
o a-3(1+w), we have
G/3)a2
= (8
G/3)a2
o a-3(1+w) = Ho2
o/
c,o a-3(1+w) = Ho2 a-(1+3w)
da/dt = Ho a-(1+3w)/2
a(1+3w)/2
da = Ho
dt
a =
[(3 + 3w)/2 . t/tH]2/(3+3w)
| during the radiation era: | a t1/2 |
| during the matter era: | a t2/3 |
| during the vacuum era: | a et (from da/dt a) |
2
= -4
G
In General Relativity, a similar relation gives the acceleration:
G (
+ 3p/c2) = -(4/3)
G
(1 + 3w)
, but it includes a pressure term.
(1 + 3w), then
if w < -1/3 we find that gravity is repulsive!
0.1.
.
v is +ve and adds to gravity, while pv is -ve and dominates, giving net acceleration.
internal energy decreases
internal energy increases
vc2 behaves the same way
An extreme example: imagine a strange piston with a little "strange water" in it.
You pull extremely hard, with force F = p x A, with p = 9 x 1020 dyne cm-2 (~1015 atm) and A = 1 cm2
the piston slowly moves out by d = 1 cm -- you have spent F x d = 9 x 1020 erg of energy.
To your surprise, the piston now contains an additional cm3 of water!
Your 9 x 1020 erg were converted to
9 x 1020/c2 = 1 gm of new water.
(Note: since dark energy is 6.8 x 10-30 gm cm-3, it only requires 6 x 10-9 dyne cm-2 tension to create.
However, you can't verify this experimentally because there is vacuum on both
sides of the piston!).
For normal matter, expansion spreads mass out, raising
the gravitational energy
The loss of energy to the gravitational field comes out of the kinetic energy of expansion -- it decelerates
For radiation, the situation is even worse, since expansion affects both M and R in
the gravitational term.
But for vacuum, the M2 term beats out the R term, and the gravitational
energy is more negative
(one detail: this only becomes true for regions larger than the Hubble volume).
The whole thing is not unlike a ball falling downwards:
by moving down, R is smaller, so Ugrav is more negative.
to conserve energy, the ball must pick up positive kinetic energy, and hence it accelerates.
For a vacuum dominated universe, a larger universe has more negative binding
energy (G M2/R increases)
Some of this gravitational energy is used to make the additional vacuum.
Where does the rest go? Into the kinetic energy -- the fluid accelerates
Thus, a vacuum dominated universe "falls downwards" by expanding and accelerating.
o:
o) d
o = (8
/c3)
o2 [exp(h
o/kTo) - 1]-1 d
o
1, the corresponding frequency is
=
o / a, giving d
= d
o / a
) d
=
n(
o) / a3 d
o
) d
=
(8
/c3)
2 a2[exp(h
a/kTo) - 1]-1 a d
, giving
) d
=
(8
/c3)
2 [exp(h
/kToa-1) - 1]-1 d
| T = To / a = To (1 + z) |
systems:
< v2 >, while for BB: T
<
>
=
o / a, ie v = vo / a
dv/v = -da/a with solution:
a-1 or, for v = vo at a = 1, we have v = vo/a
as time passes a increases & v decreases; hence random motions decrease and T drops
No vo2 (m/2
kTo)3/2 exp(-mvo2 / kTo) dvo (N and n in number per cm3)
at time when a
1, we have v = vo/a and dv = dvo/a
particle conservation also requires n(v)dv = n(vo)/a3 dvo and N = No/a3
Substituting these into the MB relation, we get:
a3N a2v2 (m/2
kTo)3/2 exp(-mv2a2 / kTo) a dv
N v2 (m/2
k(To/a2))3/2 exp(-mv2 / k(To/a2)) a dv
| T = To / a2 = To (1 + z)2 |
a-2
a-1
At z ~ 1100 both have T
3000K; at z = 0, T
2.725 K, while Tmatter
2.48 mK.
In practice, this cooling for the baryonic gas never occurs:
= -8
G/c2
Tµ
& Tµ
are both 4 × 4 matricies, suggesting 16 equations, though symmetries reduce this to 10.
= 0,1,2,3 denote 1 time & 3 space coordinates (e.g. ct, x, y, z or ct, r,
,
).
= 0), and momentum
(µ,
= 1,2,3) in the system
Loosely speaking, this section looks at the geometry part, G.
The next section looks at the dynamical part, T, and how it relates to G.
r2; a sphere has area 4
r2 and volume 4/3
r3
Adding Newton's intuitively plausible independent time, t, yields a 4 coordinate space-time
2 where ds2
(ds)2, etc.
ds2 = dx2 + dy2 + dz2 = dr2 + r2 (d
2 +
sin2
d
2)
= dr2 + r2 d
2
Note that the choice of cartesian or polar (or any other) coordinate system is unimportant
They are equivalent and define the same space.
ds) to construct a triangle
its interior angles sum to 180o; and so on.
from a pole, where r is measured along the surface [image]
2
2)
2 contribution to ds2.
ang =
+ A/R2
any measured triangle allows you to obtain the radius of curvature, R
for the sphere, all triangles give the same R: the space is homogeneous and isotropic
the sphere has finite circumference (2
R) and finite surface area (4
R2).
2 where d
2 = d
2 + sin2
d
2, r is
a "straight" line from origin.
To get a feel for the odd nature of this space, imagine holding a laser pointer with visible beam (r)
Turn it through 1o (d
= 1o):
)
/2 the sweep begins to decrease for larger r
R.
If you explored geometry living in this kind of space, you would not recover the Euclidean results
In 1840 Gauss actually tried to measure the curvature of space by surveying big triangles [image].
Of course, his modestly accurate measurements only recovered the Euclidean value of 180o
But in principle he could have discovered the non-Euclidean terrestrial Schwarzschild metric.
(in fact, R ~ 1AU, and a 30 km triangle deviates from 180o by ~10-8 arcsec).
R) and volume (2
2R3)
ang =
- A/R2 which is less than 180o
ds2 = -c2 dt2 + dr2 + r2 (d
ds2 = -c2 dt2 + dr2 + R2 sinh2(r/R) (d
One can also replace (d
As you can see, the three metrics above are all of this kind: as r
Of course, the second derivatives do not vanish, and it is these that define the
curvature.
Light moves along special null geodesics, so named because ds = cd
We can also use a freely moving object to define a "straight line".
Curvature
k
d
2
coefficient Parallel
Lines Triangle
Angles Sphere
Area Sphere
Volume Global
Form
Positive
+1
R2 sin2(r/R)
Converge
> 180
< 4
r2 < (4/3)
r2 Closed
Flat
0
r2
Never meet
180
4
r2 (4/3)
r2 Open
Negative
-1
R2 sinh2(r/R)
Diverge
< 180
> 4
r2 > (4/3)
r2 Open
(iv) Adding Time
The 3-D + 1-t metrics for positive, flat, and negative space-times become:
ds2 = -c2 dt2 + dr2 + R2 sin2(r/R) (d
2 + sin2
d
2)
2 +
sin2
d
2)
(Minkowski space-time).
2 + sin2
d
2)
2 +
sin2
d
2) with
d
2, the angle between the two events on the sky,
and group them into a single expression, using Sk(x) = sin(x), x, sinh(x) for k = +1, 0, -1:
ds2 = -c2 dt2 + dr2 + R2 Sk2(r/R) d
[ Note: I've adopted Peacock's notation for Sk, rather than Ryden's ]
2
-c2d
2, where d
is the Lorentz invariant proper time interval.
Indeed, the second is the spacetime of special relativity, and is called Minkowski spacetime.
flat geometry is rooted in the Pythagoraean relation (e.g. triangles have
ang = 180o).
Although more general geometries are curved, many are locally flat (e.g. in 3-D: a sphere)
expanding the metric to first order at any location gives a quadratic form.
Such geometries are called Reimannian and the spacetimes of GR are all of this kind. Why?
Because locally the Equivalence Principle demands a Minkowski spacetime of Special Relativity.
0, they are locally flat.
Physically, these give tidal forces which are apparent across regions of finite size.
(v) Geodesics
because straight lines are the shortest distance between two points.
E.g. on the 2-D surface of a sphere, geodesics are great circles
(hence: "aphrodisiacs" are great circles passing through Africa, ho ho).
it's minimum energy state would occupy the shortest distance.
Fermat's principle ensures they take the path of least time
the shortest path
this occurs because longer paths interfere destructively (cf Feynman's little book: QED).
Recall Newton's 1st law:
"objects free from external forces remain at rest or in uniform motion in a straight line"
(its wavefunction behaves just like the light waves: longer paths interfere destructively).
= 0 (light never feels time)
Recall, in GR gravity is not a force; instead mass curves space, and objects "follow" the space
Einstein's version of Newton's 1st law becomes:
free falling objects move along "straight lines" (geodesics) in the curved 4-D space-time.
e.g. Earth's orbit is curved in 3-space, but follows a geodesic in the 4-D space-time near the sun.
These form a diverging non-intersecting bundle with common origin in the big bang.
(This is known as Weyl's postulate (1923), and it ensures a legitimate cosmic proper time).
In practice, this means we only see things which lie on our past light cone
(a light cone is a conic surface in a 3-D spacetime, in which the 4th space axis is omitted)
World lines need not be geodesics; for example if they are acted on by a force.
you, for example, held up by the earth's surface, follow a world line, not a geodesic.
Conversely, geodesics are all world lines: the path through space-time of a freely falling object.
On large scales (> few Mpc): these assumptions are excellent [see sec 2a-c]
On intermediate scales, where |
/<
>| < 1 they are still useful:
On small scales, where 
/<
> >> 1 they are poor assumptions:
ds2 = -c2 dt2 + a(t)2 [ dro2 + Ro2 Sk2(ro/Ro) d 2 ]
|
where ro is the comoving proper distance (ie as measured today) to an object.
This looks very familiar!
1/Ro2) .
coefficient
Please don't think of R(t) as "the radius of the universe"; it is a measure of spatial curvature
although for k = +1 it yields roughly the correct total volume, for k = -1 it is negative.
Also, the limiting condition near k = 0 with R
is well behaved, since R sin(r/R)
r.
it comes just from requiring isotropy & homogeneity at all times.
= 0 and so ds = -c2d
2 = -c2dt2 giving t = 
= 0, and "at time t" means dt = 0, so the RW-metric gives
ds = a(t) dro and the total proper distance is r =
ds =
a(t) dro = a(t)
dro = a(t) ro
= 0 and ds = 0
c dt/a = dro
c dt/a =
dro = ro which is constant
Two photons are emitted at te and te +
te and arrive
at times to and to +
to
During the time te +
te to to both photons are in flight and so
dt/a for this interval is the same.
But for the full trip
dt/a is also the same, so the small start/finish contributions must be equal:
te / a(te) =
to / a(to)
to /
te =
a(to) / a(te) = 1 / a(te) (since a(to)
1)
This tells us that the duration of any event we witness is dilated by a factor
a(te)-1
A heuristic explanation of this dilation (simiar to a normal Doppler effect) was given
in [sec 3e]
As mentioned there, the dilation has been seen in the lengthened light curves of high-z supernovae
te and
to to be the time between wavecrests of light, we have the cosmological redshift:
to /
te =
e /
o =
o /
e = (1 + z) = a(te)-1
Once again, it is best to think of redshift as a change in scale factor during the photon's journey.
(v) Total Cosmic Volume
only sweeps out a distance: a(t) Ro sin(ro/Ro) d
a(t) Ro sin(ro/Ro), and the full area is: 4
a(t)2 Ro2 sin2(ro/Ro)
a(t) Ro
a(t)2 Ro2
sin2(ro/Ro) dr = 2
2 a(t)3 Ro3
as expected, the volume grows with a(t)3 and is close to the value for a 2-sphere of radius R
for an open universe the integral diverges because (i) the area diverges, and (ii) r
= 8
G/c2 Tµ
: spacetime is curved by the distribution of cosmic
energy & momentum.
It is now time to introduce GR so we can derive expressions for a(t), Ro and k
Fortunately (for you and me) the treatment will be heuristic, brief, and goal oriented.
vector
tensor.
2
= -4
G
q:
2 V = -
q /
o
(c2
2 -
2 /
t2) Aµ = -jµ /
o
q while j1,2,3 are the x, y, z currents
mo
This second aspect undermines a vector treatment, and a tensor treatment is
necessary.
Instead of a 4-vector mass/momentum current, we need a 4 × 4 mass/momentum matrix
Of course, relativistically "mass" is superceeded by energy and we speak of
Tµ
:
the "energy-momentum" tensor (or "stress-energy" tensor).
Here, µ and
are four (1 time, 3 space) coordinate indices, (eg ct, x, y, z; or ct, r,
,
)
has 4 × 4 = 16 elements, arranged in a square.
is diagonal.
c2 is the total energy density
T1,1, T2,2, T3,3 = < pxpx >c2 / E is the x-momentum density
px the x-pressure (y, z etc)
Now, pressure is isotropic, so px = py = pz = p (don't confuse momentum p with pressure p)
So Tµ
= diag (
c2, p, p, p) (all off-diagonal elements are zero).
(iii) Gµv : The Curvature Tensor
, what about Gµ
?
2 in the Newtonian Poisson equation).
,
,
with 44 = 256 elements.
, and its scaler trace, the Ricci curvature, R.
= Rµ
- ½ gµ
R where gµ
are the metric coefficients]
the geometry is Reimannian.
is diagonalEvaluating the elements for the RW-spacetime, one obtains:
G1,1 = G2,2 = G3,3 = -1/a2 [ 2 a (d2a/dt2) + k c2/Ro2 + (da/dt)2]
to the same elements of Tµ
& add the proportionality constant:
G
= 8
G/c2 T0,0
Gj,j =
-1/a2 [ 2 a (d2a/dt2) + k c2/Ro2 + (da/dt)2] = 8
G p/c2 = 8
G/c2 Tj,j
Combining these, we arrive at two fundamentally important cosmic equations
(da/dt)2 = (8 G/3) a2 - k c2/Ro2 | The Friedmann Equation, or Energy Equation |