![]() |
||||||
| Are two trains, moving at different but constant velocities, in the same inertial reference frame? Do two non-inertial reference frames imply that one frame is accelerating? | |
|
"Different" velocities mean different frames. That includes the case where they have the same speed but are moving in different directions. In special relativity if a frame is noninertial it must be accelerating; it's either moving at constant velocity or it's accelerating. Two noninertial frames will also be accelerating with respect to each other, unless they are accelerating in exactly the same way (i.e. two observers could be in the same accelerating frame at different locations and at rest with respect to each other). (The situation is a bit more complicated in general relativity because inertial reference frames can generally be defined only locally.) |
|
| Let's say that you launch two spaceships going in opposite directions. Eventually, both spaceships have a velocity of .75c, each in their respective directions. From earth, this is fine because neither speed exceeds c, but if you take the point of view of one of the spaceships, what would the velocity of the other ship be? It would seem that to one of the ships the earth would be moving away at .75c and the other ship would be moving away at 1.5c. How can this be? | |
|
Velocities don't add up like they do in Newtonian mechanics. The relativity of space and time intervals extends to velocity. Equation 7.8 describes how to add two velocities together. For your example we have (.75+.75)/(1+.75*.75) = 1.5/1.5625 = 0.96. One can prove this relation by examining the Lorentz transform of velocity = dx/dt. This involves some mildly complicated algebra. |
|
| OK, maybe I see why clocks should run slow, but why must there also be a length contraction? | |
|
The second postulate of relativity requires the speed of light to be the same in all reference frames. Since speed is a change of distance divided by a change of time, if time changes (time-dilation) then length must change too to maintain the constancy of light. |
|
| Does a supersonic airplane (such as the Concorde) noticeably shrink in size, and if so how are they built to deal with that? | |
| The shrinkage (Lorentz contraction) due to its motion is not measurable for the Concorde at the speeds it is moving. However, even if we were talking about a measurable contraction of a relativistic spaceship it is not necessary to worry about Lorentz contraction in ship design. The contraction is relative, and is measured in the frame moving with respect to the ship. In the ship's own frame it has its proper length. As long as it is moving inertially there are no forces on the spaceship. | |
| Is there any way to visualize length contraction rather than just considering the mathematical equation for it? | |
|
The spacetime diagram can provide a graphical illustration of length contraction, i.e. you can see how a standard length is shorter in other frames compared to its rest frame. |
|
| How can simultaneity be relative? | |
|
Nobody has a problem with realizing that two different reference frames moving with respect to each other don't regard two events at different times as occurring at the same point in space. In special relativity we find that two different observers also don't regard two events separated in space as happening at the same time. We are used to thinking of time unfolding, and time being the same for all possible observers. This isn't the way it is in SR. Simultaneity is defined as "things happening at the same time." We might also define it in this way: Two events (two points in spacetime) are simultaneous in a given frame if a light signal emitted midway between the spatial locations of those two events arrives at those events. An example would be a lightbulb flashing at the center of a train car. In the train-car's frame the light hits the front and the back of the car at the same time, hence those two events are simultaneous. But to an observer watching the train car go by at some speed the two events cannot be simultaneous because the rear of the train comes forward to meet the light signal while the front of the train moves ahead of the light signal (put another way, the flashing of the light doesn't occur midway between the two events, according to the ground-based observer, because the train is in motion). |
|
| Why is the spacetime interval "invariant" under the Lorentz transformation? What does it mean? | |
|
The first thing to understand is that time intervals and space intervals are relative, i.e., the value an inertial observer would get for a measurement of either of them depends on the observer's frame. This is different from what we are used to thinking. Space intervals and time intervals vary between frames according to the Lorentz transformation formula (the gamma or boost factor). If you were to take the definition for the space-time interval, plug in the lorentz transformation terms as appropriate to change delta t and delta x to a different frame, you would find that the terms cancel in such as way as to leave delta s unchanged, despite the transformation to a different frame. This means that all observers, no matter what their relative motion, will measure the same delta s even though their individual delta t and delta x intervals will be different. The agreement between all the inertial observers means that the quantity is invariant. But what is delta s, the space time interval? In a mathematical sense, it is just a thing constructed in such a way that the Lorentz tranformation terms cancel out, that is it is designed to be an invariant quantity. Does it have a physical interpretation? It is a measure of a "distance" in spacetime. In ordinary space, a distance can be defined that is invariant under the Galilean transformation: the familiar Pythagorean rule is one such mathematical rule that gives an invariant distance even though separate observers' definition of x and y might be different. The spacetime interval extends this concept to spacetime. Since proper time is a distance in a geometry, it differs along different paths in that geometry, just as the spatial distance along a path through space depends upon the path. Consider two events in spacetime, separated by a timelike interval, and suppose that several clocks travel along separate worldlines between those two events. Each clock will measure a different proper time along its worldline, but the clock which travels along an inertial path (a straight line in spacetime) will register the longest elapsed proper time. This property of spacetime is in some respects opposite to the familiar Euclidean geometry, in which the straight line is the shortest distance between two points. |
|
| Is density relative? | |
|
Yes. Density is mass per unit volume, so if a block of some density is moving past you, length contraction would decrease the volume while the mass would increase by the relativistic equation. |
|
| The text says that it requires too much energy to realistically reach speeds close to the speed of light. But aren't all speeds relative? Suppose I am travelling 0.7c with respect to the Earth. My ships engines and fuel are also travelling at this speed. Shouldn't it be easy to accelerate to 0.8c without too much effort? How is this more energetically expensive than accelerating from rest to 0.1c? From the ships and the engines point of view, the ship is at rest. I'm confused about the difficulties of getting closer to light speed. With respect to whom? | |
|
Speeds are indeed relative, so you must compute the change in speed from the frame of the spaceship. In this case you wish to accelerate from 0.7c to 0.8c, both measured with respect to the Earth. By the relativistic velocity addition law, the velocity change is not 0.1c in the frame of the spaceship, but is 0.23c. In the spaceship frame, the energy required is given by the corresponding boost factor, which in this case is 1.028. The additional energy needed is thus 0.028mc2. The change in boost factor as measured from the Earth frame is Gamma(.8c) = 1.67 - Gamma(.7c)=1.40; the difference is 0.27, so the additional energy required will be 0.27mc2, as measured in Earth's frame. Why the difference? The straightforward answer is that a measurement of energy is relative. However, in either frame the amount of energy required to accelerate by the same factor will increase as the ship's speed increases, because of the dependence of the boost factor upon the square of the speed. Accelerating from 0.8c to 0.9c in the Earth's frame corresponds to an increase of 0.35c in the spaceship's frame. In the spaceship frame, the energy required for the increase is 0.06mc2, while in the Earth frame it is 0.68mc2; in both cases substantially more energy is required to go from 0.8c to 0.9c than to go from 0.7c to 0.8c. |
|
| Is there ever a case where someone's clock appears to be running faster than your own from your frame of reference? | |
| Yes, but only if your frame of reference is an accelerated one, and/or you are deep inside a gravitational field. Gravitational time dilation then causes your clock to run slow as you see it compared to a clock up at high altitude. | |
|
Copyright © 2005 John F. Hawley |